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4 years ago

What is -4 times 7/10

Mathematics

1 answer:

BabaBlast [244]4 years ago

5 0

Answer:

-280

Step-by-step explanation:

because,

-4(7)= -28

-28(10)= -280

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What’s the slope for RS

Annette [7]

Answer: 4/2

Step-by-step explanation: Rise over run. From point S to R it goes up 4 and over 2.

6 0

3 years ago

Identify the graph of f(x)=4^x

Wittaler [7]

Answer:

the first one

Step-by-step explanation:

The correct one is the one in the top left corner.

A great website to find out things like this is

https://www.mathpapa.com/algebra-calculator.html

5 0

4 years ago

three times the lesser of two consecutive even integers is 6 less than six times the greatest number. find the integers.

kakasveta [241]

3x-6=6(x+2) 3x-6=6x+12 3x-6x=6+12 -3x=18 X= 18/-3 X= -6 first number . For second number you substitute x+2. -6+2=-4

3 0

3 years ago

What is the domain of the function y = 3 l n x graphed below? On a coordinate plane, a curve starts in quadrant 4 and then incre

VladimirAG [237]

Answer:

<h2>X greater-than 0</h2>

Step-by-step explanation:

The given function is

$y=3ln(x)$

Which is a logarithm function. An important characteristic of logarithms is that their domain cannot be negatice, because the logarithm of a negative number is undefined, the same happens for x=0.

Therefore, the domain of this function is all real numbers more than zero.

The image attached shows the graph of this function, there you can notice its domain restriction.

So, the right answer is the first choice: x greater than 0.

5 0

4 years ago

Determine the formula for the nth term of the sequence:<br>-2,1,7,25,79,...

rodikova [14]

A plausible guess might be that the sequence is formed by a degree-4* polynomial,

$x_n = a n^4 + b n^3 + c n^2 + d n + e$

From the given known values of the sequence, we have

$\begin{cases}a+b+c+d+e = -2 \\ 16 a + 8 b + 4 c + 2 d + e = 1 \\ 81 a + 27 b + 9 c + 3 d + e = 7 \\ 256 a + 64 b + 16 c + 4 d + e = 25 \\ 625 a + 125 b + 25 c + 5 d + e = 79\end{cases}$

Solving the system yields coefficients

$a=\dfrac58, b=-\dfrac{19}4, c=\dfrac{115}8, d = -\dfrac{65}4, e=4$

so that the n-th term in the sequence might be

$\displaystyle x_n = \boxed{\frac{5 n^4}{8}-\frac{19 n^3}{4}+\frac{115 n^2}{8}-\frac{65 n}{4}+4}$

Then the next few terms in the sequence could very well be

$\{-2, 1, 7, 25, 79, 208, 466, 922, 1660, 2779, \ldots\}$

It would be much easier to confirm this had the given sequence provided just one more term...

* Why degree-4? This rests on the assumption that the higher-order forward differences of $\{x_n\}$ eventually form a constant sequence. But we only have enough information to find one term in the sequence of 4th-order differences. Denote the k-th-order forward differences of $\{x_n\}$ by $\Delta^{k}\{x_n\}$ . Then

• 1st-order differences:

$\Delta\{x_n\} = \{1-(-2), 7-1, 25-7, 79-25,\ldots\} = \{3,6,18,54,\ldots\}$

• 2nd-order differences:

$\Delta^2\{x_n\} = \{6-3,18-6,54-18,\ldots\} = \{3,12,36,\ldots\}$

• 3rd-order differences:

$\Delta^3\{x_n\} = \{12-3, 36-12,\ldots\} = \{9,24,\ldots\}$

• 4th-order differences:

$\Delta^4\{x_n\} = \{24-9,\ldots\} = \{15,\ldots\}$

From here I made the assumption that $\Delta^4\{x_n\}$ is the constant sequence {15, 15, 15, …}. This implies $\Delta^3\{x_n\}$ forms an arithmetic/linear sequence, which implies $\Delta^2\{x_n\}$ forms a quadratic sequence, and so on up $\{x_n\}$ forming a quartic sequence. Then we can use the method of undetermined coefficients to find it.

5 0

2 years ago