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Alchen [17]
3 years ago
10

Helpp plzzz I will mark brainliestttt

Mathematics
2 answers:
tangare [24]3 years ago
3 0
294cm^2
49 x 6 (sides)
cestrela7 [59]3 years ago
3 0

Answer:

294

Step-by-step explanation:

We are given the area of 1 face of a cube. The area is 49. Now if their are 6 faces in a cube, and all faces of a cube are the same, then we multiply 49*6 = 294.

P.S. I don't understand the boxes thing but I have the answer :)

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(4n⁴-8n+4) - (8n²+4n⁴+1) <br> How do I simplify this expression?
Kobotan [32]

Answer:

-4n^4-4n^2-8n+3

Step-by-step explanation:

you combine the like terms

8 0
3 years ago
Find the volume of this square<br> based pyramid.<br> 5ft<br> 6 ft<br> [? ]ft
Sav [38]

Answer:

48 ft³

Step-by-step explanation:

To find the height, you can use the slant height and the base.

Using the Pythagorean Theorem and 3 as the triangle's base,

a²+b²=c²

3²+b²=5²

9+b²=25

b²=16

b=4

The height of the pyramid is 4.

Volume formula for the pyramid is \frac{1}{3} *b*h

Inserting our measurements:

\frac{1}{3} *6*6*4=\\2*6*4=\\12*4=\\48

5 0
3 years ago
A resort hotel rents bicycles for 20 plus and hourly rate of $6. A nearby hotel rents bicycles for 15$ plus an hourly rate of $8
max2010maxim [7]
What are you trying to slove?
8 0
2 years ago
Help pleaseeeeeeeeeeeeeeeeeeeeee
xxTIMURxx [149]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand
Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 18.6, \sigma = 5.9

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 18.6}{5.4}

Z = 0.44

Z = 0.44 has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768

This probability is 1 subtracted by the pvalue of Z when X = 20.4. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{20.4 - 18.6}{0.6768}

Z = 2.66

Z = 2.66 has a pvalue of 0.9961

1 - 0.9961 = 0.0039

0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

4 0
2 years ago
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