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ipn [44]
2 years ago
13

“Nothing great was ever accomplished by a realistic person.” Do you agree? Why or why not?

SAT
1 answer:
qaws [65]2 years ago
8 0

Answer:

yes becasue you have to have unrealistic, for lack of a better word, thoughts and ideas

Explanation:

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i am just finnna make u mad

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3 years ago
Who are the characters in the poem "the mending wall"?
Paraphin [41]

Answer:

two characters: speaker and the neighbor

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6 0
3 years ago
The student hypothesizes that a greater fraction of kinetic energy is lost from the system during the collision when the speed o
topjm [15]

A greater fraction of kinetic energy is lost from the system during the collision when the speed of the first cart is greater due to inelastic collision.

<h3>What is kinetic energy?</h3>

It should be noted that kinetic energy simply means a form of energy of an object due to motion.

In this case, a greater fraction of kinetic energy is lost from the system during the collision when the speed of the first cart is greater due to inelastic collision.

Learn more about kinetic energy on:

brainly.com/question/25959744

8 0
2 years ago
How do creadvity, curiosity and mystery impact our<br> ability to grow and find our purpose?
Dominik [7]
Their wide interests and curiosity enable them to apply ideas across divergent fields, improving upon the ideas of others, synthesizing ideas, and discovering patterns from disparate fields to generate new ideas. Curiosity reveals new options even at dead ends and inspires a sense of purpose and meaning.
7 0
3 years ago
The point (−2,4) lies on the curve in the xy-plane given by the equation f(x)g(y)=17−x−y, where f is a differentiable function o
Nikitich [7]

The value of \frac{dy}{dx} is -3. \blacksquare

<h2>Procedure - Differentiability</h2><h3 /><h3>Chain rule and derivatives</h3><h3 />

We derive an expression for \frac{dy}{dx} by means of chain rule and differentiation rule for a product of functions:

\frac{d}{dx}[f(x)\cdot g(y)] = [f'(x)\cdot \frac{dx}{dx}]\cdot g(y) + f(x) \cdot [g'(y)\cdot \frac{dy}{dx} ]

\frac{d}{dx}[f(x)\cdot g(y)] = f'(x)\cdot g(y) +f(x)\cdot g'(y)\cdot \frac{dy}{dx} (1)

If we know that f(x) \cdot g(y) = 17-x-y, f(-2) = 3,<em> </em>f'(-2) = 4,<em> </em>g(4) = 5 andg'(4) = 2, then we have the following expression:

-1-\frac{dy}{dx} = (4)\cdot (5) + (3)\cdot (2) \cdot \frac{dy}{dx}

-1-\frac{dy}{dx} = 20 + 6\cdot \frac{dy}{dx}

7\cdot \frac{dy}{dx} = -21

\frac{dy}{dx} = -3

The value of \frac{dy}{dx} is -3. \blacksquare

To learn more on differentiability, we kindly invite to check this verified question: brainly.com/question/24062595

<h3>Remark</h3>

The statement is incomplete and full of mistakes. Complete and corrected form is presented below:

<em>The point (-2, 4) lies on the curve in the xy-plane given by the equation </em>f(x)\cdot g(y) = 17 - x\cdot y<em>, where </em>f<em> is a differentiable function of </em>x<em> and </em>g<em> is a differentiable function of </em>y<em>. Selected values of </em>f<em>, </em>f'<em>, </em>g<em> and </em>g'<em> are given below: </em>f(-2) = 3<em>, </em>f'(-2) = 4<em>, </em>g(4) = 5<em>, </em>g'(4) = 2<em>. </em>

<em />

<em>What is the value of </em>\frac{dy}{dx}<em> at the point </em>(-2, 4)<em>?</em>

3 0
2 years ago
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