1. The molarity of the stock solution is 1.26 M
2. The molarity of the diluted solution is 0.126 M
<h3>1. How to determine the molarity of stock solution </h3>
From the question given above, the following data were obtained
- Mole of KIO₃ = 6.05 mole
- Volume = 4.8 L
- Molarity of stock solution =?
Molarity = mole / Volume
Molarity of stock solution = 6.05 / 4.8
Molarity of stock solution = 1.26 M
<h3>2. How to determine the molarity of the diluted solution </h3>
- Molarity of stock solution (M₁) = 1.26 M
- Volume of stock solution (V₁) = 10 mL
- Volume of diluted solution (V₂) = 100 mL
- Molarity of diluted solution (M₂) =?
M₁V₁ = M₂V₂
1.26 × 10 = M₂ × 100
12.6 = M₂ × 100
Divide both side by 100
M₂ = 12.6 / 100
M₂ = 0.126 M
Complete question
An aqueous potassium iodate stock solution is made by dissolving 6.05 mol KIO3 in sufficient water for the final volume of the solution to be 4.80 L.
Calculate the molarity of the stock KIO3 solution.
A 10.0 mL aliquot is removed from the described stock solution and diluted to a total volume of 100.0 mL.
Calculate the molarity of the dilute solution
Learn more about dilution:
brainly.com/question/15022582
#SPJ1
Equal Opportunity Representatives and Officers :: Summary. Monitor and evaluate compliance with equal opportunity laws, guidelines, and policies to ensure that employment practices and contracting arrangements give equal opportunity without regard to race, religion, color, national origin, sex, age, or disability.
Answer:
Luke can get better at math if he challenges his brain to practice.
Explanation:
The chemical equations that show a reaction that occurs when someone takes an antacid are;
- HCl + NaHCO₃ -> NaCl + H₂O + CO₂
- 2HCl + CaCO₃ -> CaCl₂ + CO₂ + H₂O
- 2HCl + Mg(OH)₂ -> MgCl₂ + 2H₂O
<h3>What is the correct chemical equation?</h3>
Hydrochloic acid would normally react with the basic substances in the stomach. Now, these substances that react with hydrochloric acid in the stomach are magnesium hydroxide, sodium bicarbonate and calcium carbonate.
Thus, from the above dewscription, the chemical equations that show a reaction that occurs when someone takes an antacid are;
- HCl + NaHCO₃ -> NaCl + H₂O + CO₂
- 2HCl + CaCO₃ -> CaCl₂ + CO₂ + H₂O
- 2HCl + Mg(OH)₂ -> MgCl₂ + 2H₂O
Read more about chemical equations at; brainly.com/question/11231920?source=archive
