(1) R+G+B=50
(2) R=B+6
(3) G=B-4 so substitute G in (1)
R+B-4+B=50 substitute (2) in here
B+6+B-4+B=50 group like terms and solve
3B+2=50
3B=50-2
B=48/3=16 substitute in (2) and (3)
R=16+6=22
G=16-4=12
Check
22+12+16=50✅
Answer:
f(x)= 1 - 2x
Step-by-step explanation:
Answer:
y= -2x + 12
Step-by-step explanation:
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Answer:
y=(x-4)²
Step-by-step explanation:
(a-b)²=a²-2ab+b²
(x-4)²=x²-2×x×4+4²
(x-4)²=x²-8x+16
