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Volgvan
3 years ago
12

Simplify 22w/55 2/5 22/55 2w/11 2w/5

Mathematics
2 answers:
maxonik [38]3 years ago
6 0
2w/5 because you have to divide whole numbers by 11,and leave the variable
tangare [24]3 years ago
4 0

Answer:

2w/5

Step-by-step explanation:

Divide whole numbers by 11,leave the variable.

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You have $1,500 to spend over a five month semester to cover your living expenses. In the first month, you spend $150 at restaur
alekssr [168]

Answer:

$250

Step-by-step explanation:

1st month you spent $300. And the flight back is $200. 300+200=500. 1500-500=1000. Yoy have 1000 dollars to spend in 4 months. 1000/4=250, so each month you can spend $250.

6 0
3 years ago
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The level of a lake was 8 inches below normal. It decrease 1 1/4 inches in June and 2 3/8 inches more in July. What was the new
zloy xaker [14]

Answer:

Step-by-step explanation:

1

the initial level is below normal so it is represented by a negative number. the level continued to decrease in June and July so those changes are also represented by negative numbers. find the sum of these values to find what the new level was with respect to the normal level

2

write the mixed numbers as improper fractions

3

get common denominator

4

add the numerators since all the numbers are negative and have a common denominator. write the improper fraction as a mixed number

3 0
3 years ago
Do I have a rare user? Just asking :)
Andre45 [30]

Answer:

lol yes?

Step-by-step explanation:

5 0
3 years ago
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Write the expression as one<br> involving only sin x and cos x.<br> sin 2x + cos x
AfilCa [17]

Answer:

sin 2x + cos x =  2 sin x cos x + cos x = (2 sin x + 1)cos x

Step-by-step explanation:

Given the expression: sin 2x + cos x,

then we can use the formula: sin 2x = 2 sin x cos x, which gives:

sin 2x + cos x =  2 sin x cos x + cos x = (2 sin x + 1)cos x

So there you have two expressions in terms of sin x and cos x, as requested. :D

6 0
2 years ago
Find the area of the rhombus
MAXImum [283]
<h3> Solution :-</h3>

Area of rhombus :-

\bf  \star \:  \:  \boxed{ \bf  \dfrac{d_{1}d_{2}}{2} }

\sf \longrightarrow d_{1} = 4 \sqrt{3}  + 4 \sqrt{3} = 8 \sqrt{3}

\sf \longrightarrow d_{2}  = 4 + 4 = 8

Area of rhombus :-

:  \implies \sf  \dfrac{8 \sqrt{3} \times 8 }{2}

:   \implies \sf  8 \sqrt{3}  \times 4

:  \implies \bf 32 \sqrt{3}  \:  {m}^{2}

6 0
3 years ago
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