Answer: <span>A square inscribed in a circle.
</span>
Justification:
Note that by making two perpendicular lines that intersect each other in the center of the circle, he obtains 4 equidistant points on the circumference.
So, joining each pair of neighbouring points, the image will reveal 4 congruent sides joining at right angles (90°). This is the image of a square with the four vertices on the circumference.
<span>Three powers with whole number bases that have values greater than 120 and less than 130 are:
</span>11² = 11 x 11 = 121
<span>5³ = 5 x 5 x 5 =125 </span>
<span>2⁷ = 2 x 2 x 2 x 2 x 2 x 2 x 2 = 128
</span>
Circumference of the outer circle = 2πr = 2π(6) = 12π
circumference of the outer arc = 120/360 x 12π = 12.57cm
circumference of the inner circle = 2πr = 2π(5) = 10π
circumference of the inner arc = 120/360 x 10π = 10.47 cm
Difference in length = 12.57 - 10.47 = 2.1cm (1 d.p.)
Answer: 2.1cm
Is it plus, minus, multiplication or division?
1. The monomial, x, a factor of the expression x2 + 15x "represents the side length, in centimeters, of the photo." So Choice A.
2. The binomial, (x + 15), a factor of the expression x2 + 15x is Choice D because x is the length of the photo plus the 15 cm left of the frame.
3. The first-degree term of the expression x2 + 15x is the area of the photo since "x" is the length. So, Choice C.
4. The second-degree term of the expression x2 + 15x is the area of the frame around the picture. That leaves us with Choice B.
