I believe that the answer is <span><span>2<span>m2</span></span>+<span><span><span>−1</span>4</span>m</span></span>+<span>7<span>4 </span></span>
Answer:
C. √2 - 1
Step-by-step explanation:
If we draw a square from the center of the large circle to the center of one of the small circles, we can see that the sides of the square are equal to the radius of the small circle (see attached diagram)
Let r = the radius of the small circle
Using Pythagoras' Theorem 
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
to find the diagonal of the square:



So the diagonal of the square = 
We are told that the radius of the large circle is 1:
⇒ Diagonal of square + r = 1





Using the quadratic formula to calculate r:




As distance is positive,
only
Answer:
a = -2
Step-by-step explanation:
I'm assuming that the equation is a + 8/3 = 2/3, and you are supposed to solve for a.
Since there are no multiples other than 1 and -1 that could multiply in any way to equal 1, those are the only numbers you can really work with
it is a possibility that a, b, and c could equal 1 but then it would go wrong when comes time to subtract since all numbers are equal and cannot subtract largest from smallest.
a logical approach would be to try -1, -1, and 1 since -1 * -1 = 1 and then 1* 1 =1
we can make a= -1 , b= -1, and c= 1
(we need b to equal -1 so that we get an answer of -1 opposed to if we made a=-1 and c=-1, all outcomes would equal 1)
-1²=1
-1³=-1
1⁴= 1
since 1 is the largest possible outcome and -1 is the lowest possible outcome you should subtract the two
1-(-1) = 1+1 = 2
The answer should be D: 2
hoped this helped at all!
Answer: round it up to 5
Step-by-step explanation:
2/3 time 7 = 14/3
14/3= 4.6
if the number after the decimal is above 5 you may round up