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2 years ago

In 3 months John collected a debt of $70.00. What was the average amount of debt John collected per month?

Mathematics

1 answer:

Shalnov [3]2 years ago

7 0

Answer:

$23

Step-by-step

Johns debt is 70.00 dollars in 3 months. 70 divided by 3 is 23.

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The probability that an egg on a production line is cracked is 0.01. Two eggs are selected at random from the production line. F

musickatia [10]

Answer:

$P(X \geq 1)=1-P(X$

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

Step-by-step explanation:

Let X the random variable of interest "number of craked eggs", on this case we now that:

$X \sim Binom(n=2, p=0.01)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(x \geq 1)=1-P(X$

And we can find the probability:

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

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2 years ago

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Verdich [7]

Answer:

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2 years ago

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oksian1 [2.3K]

Answer:

Step-by-step explanation:

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1 year ago

The cost c, for manufacturing x flags is given by c=x? -24x +39. Find the number of flags manufactured if the cost is $120.

IRINA_888 [86]

9514 1404 393

Answer:

Step-by-step explanation:

You want to find x when c = 120.

120 = x^2 -24x +39

x^2 -24x -81 = 0 . . . . . . subtract 120 to put in standard form

(x -27)(x +3) = 0 . . . . . .factor it

Solutions are ...

x = 27, x = -3 . . . . . values of x that make the factors zero

The number of flags manufactured for a cost of $120 is 27 flags.

8 0

2 years ago

Ticket for football final selling well, on Thursday 4/7 of the tickets are sold, on Friday 1/4 of the tickets are sold, What fra

sergij07 [2.7K]

Answer:

5/28

Step-by-step explanation:

1/1 represents the whole amount of tickets.

4/7 are sold on Thursday.

an additional 1/4 are did on Friday.

fraction of available tickets on Saturday are therefore

1/1 - 4/7 - 1/4 = 4/1 - 16/7 - 1/1 = 28/1 - 16/1 - 7/1 = 5/1

that means out of 28 equal parts of the total number of tickets 16+7 = 23 parts have been sold.

so, there are only 5 out of the total 28 parts available on Saturday, and the fraction of available tickets is therefore 5/28.

we could have also tried to bring both fractions to the same denominator, and found that this is 28.

and then

4/7 + 1/4 = 4/4 × 4/7 + 7/7 × 1/4 =

= 16/28 + 7/28 = 23/28

and the whole is 28/28.

so we have 28/27 - 23/28 = 5/28 left.

surprise, surprise, it is the same result ...

4 0

1 year ago