Ask question

Ask question

All categories

3 years ago

8

The sum of three whole numbers in 27. The mean of the three whole numbers is 9, and the greatest number is twice the least numbe

r.
What is the greatest number?

A. 9
B. 12
C. 18
D. 24

2 answers:

Kitty [74]3 years ago

6 0

B I think. Good luck

Alex787 [66]3 years ago

4 0

Ya I think the answer to your question is B I could be wrong

You might be interested in

Question Category: Solving Quadratic Equations by Factoring Select the correct answer. Find the solution(s) for x in the equatio

Novay_Z [31]

Answer: x = 4; x = 5

Step-by-step explanation:

The directions specify to solve by factoring

x^2 - 9x + 20 = 0

To factor, find two numbers that add to -9 and multiply to 20

-5 and -4 work

-5 + (-4) = -9

-5 * -4 = 20

(x - 4)(x - 5) = 0

x = 4, x =5

6 0

3 years ago

What are the coordinates of the center and length of the radius of the circle whose equation is X^2+6x+4y=23?

Virty [35]

Answer:

The following equation is not a circle, but a hyperbola, because you have 4y, but no y^2

Step-by-step explanation:

Please mark for Brainliest!! :D Thanks!!

For more questions or more information, please comment below!

3 0

3 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

This is similar to the last one but this is also an quiz that’s worth a major. Can anybody help?

VashaNatasha [74]

Answer:

42

Step-by-step explanation:

Shanice: 88

Greg: (88 - 4) ÷ 2 = 84 ÷ 2 = 42

3 0

3 years ago

2,6,12,20 Generalize the pattern by finding the nth term. A) 2n B) n2 + n C) 3n - 1 D) (n + 1)(n + 2)

Anna007 [38]

<span> Position Value of Term. 1. 4. </span>2<span>. 8. 3. </span>12<span>. 4. 16. 5. </span>20<span>. What expression shows the ... 1 1. </span>2<span> -5. </span>3 1<span>. 4 -5. 5 1. </span>B). n an<span>. 1 </span>2<span>. </span>2<span> 8. 3 14. 4 </span>20<span>. 5 26. </span>C). n an<span>. 1 </span>2<span>. </span>2<span> -</span>2<span>. 3 -10. 4 -26 ... </span>Generalize<span>the </span>pattern<span> by </span>finding<span> an explicit formula for the </span>nth term<span>. A) </span>n2<span> + 5. </span>B<span>). 3n + 1. </span>C<span>). </span>2n<span> + 5. </span>D). (n<span> + </span><span>1)</span>

5 0

3 years ago