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3 years ago

A triangle with an area of 37 units? is dilated by a scale factor of . Find the area of

Mathematics

1 answer:

sergeinik [125]3 years ago

7 0

Answer:

<u>58 units</u>

Step-by-step explanation:

I decided that one side is 37 units and another is 2 units, since that would make the area 37 units. (you can also use 74 units and 1 unit)

Then I multiplied 37 by 5/4, which equals a new length of 46.25 units, and I also multiplied 2 by 5/4, which equals a new length of 2.5 units.

Finally, I solve for the area of the triangle:

1/2(46.25 x 2.5) ≈ <u>58 units</u> (rounded to the nearest whole number)

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What is the leanght of the line 4 5 5 6

jolli1 [7]

Can you maybe take a picture of the problem, it’s kinda hard to understand what you’re trying to ask for

7 0

3 years ago

The midpoint of GH are M(4,3) and D(5,-6). The coordinates of the endpoint are?

Phantasy [73]

Answer:

The endpoint coordinates are (3,12)

Step-by-step explanation: $\frac{5+x^{2} }{2} =4$ $\frac{-6+y^{2} }{2} = 3$

You multiply 4 by 2 which gives you 8 and write the equation $5+x^{2} =8$ then you subtract 5 from 8 to get 3 for the x coordinate.

You multiply 3 by 2 which gives 6 and writhe the equation $-6+y^{2}=6$ then you substitute the -6 for +6 and add +6 and 6 to get 12 for the y coordinate.

To check use the midpoint formula with coordinates D and your endpoint coordinates $\frac{5+3}{2}=\frac{8}{2} =4 \\$ $\frac{-6+12}{2} =\frac{6}{2} =3$ and you get the answer for the midpoint which is (4,3)

6 0

3 years ago

If f(x) = 2x^4, then f'(3) =

valkas [14]

To find f'(3) (f prime of 3), you must find f' first. f' is the derivative of the function f(x).

Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.

The power rule for derivatives is $\frac{d}{dx} [x^{n} ] =nx^{n-1}$ . In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.

f'(x) = $\frac{d}{dx}$ (2x⁴)

f'(x) = 2(4)x³

f'(x) = 8x³

Now, to find f'(3), plug 3 into your derivative.

f'(3) = 8(3)³

f'(3) = 216

<h3>Answer:</h3>

f'(3) = 216

6 0

3 years ago

Hep asappppppppppppp

schepotkina [342]

Answer:

(6 , -1)

Step-by-step explanation:

2x+ y = 11 ----------------(I)

y = 11 - 2x --------------------(II)

$\frac{1}{2}x - 5y = 8$

Multiply the whole equation by 2

$2*\frac{1}{2}x -2*5y = 2*8$

x - 10y = 16 --------------------(III)

Substitute y = 11- 2x in equation (III)

x - 10(11 - 2x) = 16

x - 110 + 20x = 16

21x - 110 = 16

21x = 16 +110

21x = 126

x = 126/21

x = 6

Plugin x = 6 in equation (II)

y = 11 - 2*6

y = 11 - 12

y = -1

5 0

2 years ago

Question 1

777dan777 [17]

Answer:

There would be 94 tiles.

Step-by-step explanation:

The number of tiles is given by the following equation:

$n = 6 + 4p$

In which p is the current position.

How many tiles would there be in position 22?

This is n when $p = 22$ . So

$n = 6 + 4*22 = 6 + 88 = 94$

There would be 94 tiles.

8 0

3 years ago