The path of a toy rocket fired into the air can be represented by the equation h= -16t^2+75t. What is the height of the rocket a
fter 3 seconds?
1 answer:
Answer:
81 units
Step-by-step explanation:
Given data
We are given the function for the height, the height is a function of time t
h=-16t^2+75t
Hence for t= 3 , let us substitute and find the height h
h=-16(3)^2+75(3)
h= -16*9+ 225
h= -144+ 225
h= 81
Hence the height at 3 seconds is 81 units
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