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3 years ago

One package of blueberries cost 3. how many package can you buy for $9

2 answers:

7 0

3 packages.

If one pack costs three dollars, then nine divided by three is three, thus making the final answer three.

Hope this helps!

SVEN [57.7K]3 years ago

3 0

9 divided by 3= 6. You can buy 6 packages of blueberries for $9 dollars.

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In a jar, the numbers of white, black and red marbles are in ratio of 5:11:8. If the total number of marbles is 144, then how ma

iris [78.8K]

Answer:48 red marbles

Step-by-step explanation:

144÷24= 6

6*5= 30 white

6*11= 66 black

6*8= 48 red

5 0

3 years ago

Read 2 more answers

The standard error of the estimate measures the scatter or dispersion of the observed values around a __________________________

muminat

Answer:

True mean/population mean

Step-by-step explanation:

The standard error in this case gives an estimate on how far the values observed during the course of the experiment ate likely to be from the true mean/population mean.

7 0

3 years ago

How much do 15 DVDs cost at the store with the lowest unit price?

stepan [7]

Answer:

Total cost= $141.75

Step-by-step explanation:

Giving the following information:

Bernie's Bargains 6 DVDs for $56.70

Greg's Giveaways 10 DVDs for $99.70

Stan's Steals 8 DVDs for $79.68

First, we need to determine the unitary price of each and choose the lowest one:

Bernie= 56.7/6= $9.45

Greg= 99.7/10= $9.7

Stan= 79.68/8= $9.96

The lowest price is $9.45.

Now, the total cost of 15 DVDs:

Total cost= 9.45*15

Total cost= $141.75

3 0

3 years ago

Read 2 more answers

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

2 years ago

What is 2(7/10)*1/3+4/15=

NeTakaya

2(7÷10)×1÷3+4÷15=1.4×0.33+0.267
=0.462+0.267
=0.729(0.73)

4 0

3 years ago