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Romashka-Z-Leto [24]
3 years ago
8

x is less than 1 is the solution to which of the following compound inequalities? A) x is less than 4 AND x is less than 1 B) x

is greater than 3 OR x is less than 1 C) x is greater than 3 AND x is less than 1 D) x is less than 4 OR x is less than one
Mathematics
1 answer:
Julli [10]3 years ago
8 0

9514 1404 393

Answer:

  A)  x is less than 4 AND x is less than 1

Step-by-step explanation:

It's all about understanding the meaning of the English words involved.

A) any member of the solution set must be less than 1 and less than 4. Only numbers less than 1 can satisfy both requirements. (This is the correct choice.)

__

B) members of the solution set may be less than 1 or may be greater than 3. Numbers less than 1 are part of the solution set, but not all of it.

__

C) members of the solution set are required to be both greater than 3 and less than 1. There are no such numbers. The solution set is the empty set.

__

D) members of the solution set may be less than 4 or less than 1. Any number less than 4 will be a member of the solution set.

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If x=4cos(2t) and y=4sin(2t), what is the parameter of these equations
kobusy [5.1K]

Answer:

y=√(4+x)(4−x)

Step-by-step explanation:

7 0
3 years ago
Ten years ago 53% of American families owned stocks or stock funds. Sample data collected by the Investment Company Institute in
Alborosie

Answer:

a) Null hypothesis:p\geq 0.53  

Alternative hypothesis:p < 0.53  

b) z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429  

p_v =P(Z

c) So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .  

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

\hat p=0.46 estimated proportion of American families owning stocks or stock funds

p_o=0.53 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

Part a

We need to conduct a hypothesis in order to test the claim that proportion is less than 0.53 or 53%.:  

Null hypothesis:p\geq 0.53  

Alternative hypothesis:p < 0.53  

Part b

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z

Part c  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .  

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