Answer: so there are 666 multiples of 3 between 2 and 2000.
Step-by-step explanation:
the smallest number = 3 which is 3*1. The largest number is = 1998 = 3*666
multiples of 3 between {2,2000} = 666-1+1 = 666
Answer:
Step-by-step explanation:
If there needs to be 4 teachers per 21 students, you would divide the total amount of students by 21 and multiply that answer by 4. SO...:
84 ÷ 21 = 4 groups of 21 students.
4 groups × 4 teachers = 16
*** Answer***
16 TEACHERS
<h3>
Answer: Choice B</h3><h3>
y = x^2 + 7x + 1</h3>
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Proof:
A quick way to confirm that choice B is the only answer is to eliminate the other non-answers.
If you plugged x = 1 into the equation for choice A, you would get
y = -x^2 + 7x + 1
y = -1^2 + 7(1) + 1
y = -1 + 7 + 1
y = 7
We get a result of 7, but we want 9 to be the actual output. So choice A is out.
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Repeat for choice C. Plug in x = 1
y = x^2 - 7x + 1
y = 1^2 - 7(1) + 1
y = 1 - 7 + 1
y = -5
We can eliminate choice C (since again we want a result of y = 9)
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Finally let's check choice D
y = x^2 - 7x - 1
y = 1^2 - 7(1) - 1
y = 1 - 7 - 1
y= -7
so choice D is off the list as well
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The only thing left is choice B, so it must be the answer. It turns out that plugging x = 1 into this equation leads to y = 9 as shown below
y = x^2 + 7x + 1
y = 1^2 + 7(1) + 1
y = 1 + 7 + 1
y = 9
And the same applies to any other x value in the table (eg: plugging in x = 3 leads to y = 31, etc etc).
Answer:
Step-by-step explanation:
A bc he lost it so we’re subtracting and it says “700-360” underneath the problem.
Answer:
a(5) = 2 + 5^2 = 2 + 25 = 27
Step-by-step explanation:
This sequence is defined as a(n) = 2 + n^2.
Thus, a(1) = 2 + 1^2 = 2 + 1 = 3
Then a(5) = 2 + 5^2 = 2 + 25 = 27
