A Red Queen is multiplying 32 x 17. She says the answer is going to be greater than 17. Do you Disagree or Agree with her?Why?

The weights and heights of six mathematics students are given in the following table:

Verizon [17]

Answer:

c. Weight is input, height is output

Step-by-step explanation:

It is given here that "Height is a function of Weight".

which means

$Height = f(Weight)$

Thus, value of Height is depend on the value of Weight.

Thus, Weight is input variable and Height is output variable.

Hence option (c) is correct.

Further,

The variable that we can change is called the Input variable.

The Output variable depends upon the input variable, as we change the value of the input variable the value of the output variable is also get changed.

4 0

3 years ago

Ms. Thompson planted 45 flowers in her garden on Monday and planted some more flowers on

vazorg [7]

She planted 23 plants on Tuesday
68-45=23

Check✔️
45+23= 68

4 0

2 years ago

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. The value of when a

maria [59]

Answer:

Missing information

Step-by-step explanation:

5 0

4 years ago

NO LINKS!!! Please help me with these problems

nadezda [96]

<h3>Answers:</h3>

7) Center= (-1,2) Radius= $\boldsymbol{\sqrt{8}}$ Equation: $(x+1)^2+(y-2)^2 = 8$

8) Center= (3,13) Radius= 13 Equation: $(x-3)^2+(y-13)^2 = 169$

=========================================================

Explanation:

Problem 7

Let's find the distance from (-1,2) to (-3,4)

$(x_1,y_1) = (-1,2) \text{ and } (x_2, y_2) = (-3,4)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-1-(-3))^2 + (2-4)^2}\\\\d = \sqrt{(-1+3)^2 + (2-4)^2}\\\\d = \sqrt{(2)^2 + (-2)^2}\\\\d = \sqrt{4 + 4}\\\\d = \sqrt{8}\\\\$

This is the radius because it stretches from the center to a point on the circle, so $r = \sqrt{8}$

Squaring both sides will get us $r^2 = 8$

One useful template for a circle is the equation $(x-h)^2+(y-k)^2 = r^2\\\\$

(h,k) is the center

r is the radius

Let's plug in the given center (h,k) = (-1,2) and the r^2 value we found earlier.

$(x-h)^2+(y-k)^2 = r^2\\\\(x-(-1))^2+(y-2)^2 = 8\\\\(x+1)^2+(y-2)^2 = 8\\\\$

You can confirm this by using a tool like Desmos. See below.

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Problem 8

The endpoints of the diameter are (-2,1) and (8,25)

The center is the midpoint of these endpoints.

The midpoint of the x coordinates is (-2+8)/2 = 3

The midpoint of the y coordinates is (1+25)/2 = 13

The center is (h,k) = (3,13)

Now find the distance from the center to one of the points on the circle, let's say to (8,25)

$(x_1,y_1) = (3,13) \text{ and } (x_2, y_2) = (8,25)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-8)^2 + (13-25)^2}\\\\d = \sqrt{(-5)^2 + (-12)^2}\\\\d = \sqrt{25 + 144}\\\\d = \sqrt{169}\\\\d = 13\\\\$

The radius is exactly 13 units.

So,

$(x-h)^2+(y-k)^2 = r^2\\\\(x-3)^2+(y-13)^2 = 13^2\\\\(x-3)^2+(y-13)^2 = 169\\\\$

is the equation of this particular circle.

Visual confirmation is shown below.

8 0

3 years ago

Read 2 more answers

2. What would a point on the horizontal axis represent? What about on the vertical axis?

Nikitich [7]

In analytic geometry, using the common convention that the horizontal axis represents a variable x and the vertical axis represents a variable y, a y-intercept or vertical intercept is a point where the graph of a function or relation intersects the y-axis of the coordinate system. As such, these points satisfy x = 0.

A coordinate grid has two perpendicular lines, or axes, labeled like number lines. The horizontal axis is called the x-axis. The vertical axis is called the y-axis. The point where the x-axis and y-axis intersect is called the origin. The numbers on a coordinate grid are used to locate points.

7 0

3 years ago