PLEASE HELP ME WITH MY ANGLE PAIRS...If you help i will give your 5 stars, a thanks, and a brainliest :)

7th grade math!

pishuonlain [190]

Answer:

I just learned about this, and if its wrong i am so so sorry

Step-by-step explanation:

a= 120

b= 60

w= 120

x= 120

r= 105

q= 105

p= 105

8 0

3 years ago

Read 2 more answers

Which number line correctly shows 0.8 + 0.3? A number line going from 0 to 1.3 in increments of 0.01. An arrow goes from 1.1 to

steposvetlana [31]

Answer:

the second number line in the second row OR The number line D in the attached image

Step-by-step explanation:

Lets start solving the question.

(For ease of understanding each line i have labeled them please see the attachment to relate my explanation)

first read the question it i mentioned that which number line currently shows 0.8+0.3.

After reading the question it is clear that which ever line will represent it will be the addition of 08.+0.3.

here please take a note that we are dealing with a number line hence the sign also matters.

Now lets start analyzing lines one by one.To make it easy i have attached an image where i have labeled the lines as A,B,C,D,E,and F for the ease of understanding.

so take the first line A into consideration,

its starting from 0.3 and ending at 0 means its decrementing you can also determine it with the direction. any line that originates from the origin and goes to the right shows increment and addition and the lines that originates from origin and goes to the left shows decrement.

so here we can easily all those lines which are showing a leftward directions as it is decrementing and we want a line that increments 0.8+0.3

so now th lines A,B,F and H can be skipped.

We are done with analyzing line A, line B is skipped and now lets start with C.

here the line start from 0 and ends at 0.8 so it cant be the line as 0.8+0.3 yields 0.11.

so line C can't be the correct one.

Now lets consider the next line that is D.

here it starts at 0.8 and ends at 0.11 means exactly showing an increment of 0.3 also its showing a positive directions as its heading to the right.

so this is the line that correctly shows 0.8+0.3.

Now consider line E it cant be the correct line as its showing only 0 to 0.8.

and now the line that will confuse you is line G.

it starts at 0.3 and ends at 0.11 here there is increment of 0.8 though it seems like correct but it cant be the line showing 0.8+0.3 as we have to select the line that originates at 0.8 and shows an increment of 0.3 and not the one which originates at 0.3 and ends at 0.11 showing an increment of 0.8.

Also the question itself is asking 'LINE' and not 'LINES' so you can take such minute things also into Consideration for avoiding any kind of confusion.

I hope this will help you.

7 0

2 years ago

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What is the sum of the answers to the eqation?<br><img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%206x%20%2B%205%2

MAVERICK [17]

Answer:

6

Step-by-step explanation:

$x^{2}$ - 6x +5 = 0

$x^{2}$ - 6x + 9 -9 +5 = 0

[ $x^{2}$ - 6x + 9] - 4 =0

$(x -3)^{2}$ -4 = 0

$(x -3)^{2}$ = 4

(x-3) = $\sqrt{4}$ or (x-3) = - $\sqrt{4}$

(x-3) = 2 or (x-3) = -2

x = 5 or x = 1

therefore, sum of these solutions is 5+1 = 6

4 0

3 years ago

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25% of 40 emails were spam how many emails were spam

mixer [17]

10. 25% of 40 or 0.25 times 40 gives you 10.

also 25% = 1/4
so 1/4 x 40 = 10

7 0

3 years ago

Please help me with this!!!

Natalija [7]

Answer:

{A, H, M, O, P, R, S, T} = {1, 7, 5, 0, 8, 6, 4, 9}

or

{O, A, S, M, R, H, P, T} = {0, 1, 4, 5, 6, 7, 8, 9}

Step-by-step explanation:

Starting in the thousands column, we see the sum P+M+A mod 10 = M, so P + A = 10 or 11. That is, there is a carry to the next column of 1, meaning T + 1 = O, and that sum must also create a carry of 1, so S + 1 = M.

In order for T + 1 to generate a carry, we must have T = 9 and O = 0.

Now, consider the 10s column. This has 36 +A +(carry in) mod 10 = 9. So, A+(carry in) = 3.

Considering the 1s column, we have 9+0+2H+S = H+10 or H+20. We know H+S+9 cannot be 10, so it must be 20. That means H+S = 11, and (carry in) to the 10s column must be 2. Since A = 3 - (carry in), we must have A=1.

At this point, we have ... A=1, T=9, O=0, S+H=11, S+1=M.

Now, consider the 100s column. We know the carry in from the 10s column is 3, so we have 3+2A+R=A+10. Since we know A=1, this means 5+R=11, or R=6.

The carry in to the 1000s column is 1, so we have P+A+1 = 10, or P=8.

__

Our assignments so far are ...

0 = O, 1 = A, 6 = R, 8 = P, 9 = T.

and we need to find S, M, and H such that M=S+1 and S+H=11. We know S and H cannot be 2, 3, or 5, because the 11's complement of those digits is already assigned. That leaves 4 and 7 for S and H, but we also need an unassigned value that is 1 more than S. These considerations make it necessary that S=4, M=5, H=7.

Then the addition problem is ...

8197 + 90 + 5197 +491694 +19 = 505197

_____

Final assignments are ...

O = 0, A = 1, S = 4, M = 5, R = 6, H = 7, P = 8, T = 9

4 0

3 years ago