Answer:
Gradient of Line ⊥ to AB = m = 3
B) y = 3x+11
Step-by-step explanation:
A) <u><em>Firstly, finding the slope of AB</em></u>
Gradient =
Gradient =
Gradient =
Gradient =
Gradient =
<u><em>Now, the line has a gradient of negative reciprocal to this one which is perpendicular to AB</em></u>
So,
Gradient of Line ⊥ to AB = m = 3
B) <u><em>Equation of line ⊥ to AB:</em></u>
Gradient = m = 3
Now, Point = (x,y) = (-2,5)
So, x = -2, y = 5
<u><em>Putting this in slope-intercept form to get b</em></u>
=>
=> 5 = (3)(-2) + b
=> 5+6 = b
=> b = 11
<em><u>Now, Putting m and b in the slope intercept form to get the required equation:</u></em>
=>
=> y = 3x+11
Given:
Beginning Balance: 2,447.67
Less: Withdrawal <u> 231.49</u>
Total 2,216.18
Add: Credit to acct <u> 36.61</u>
Ending Balance <u> 2,252.79
</u>The new balance is $2,252.79<u>
</u>
X = low-energy lamp
y = high-energy lamp
1) 4x + 5y
2) 120= 4x + 5y
It is 70 hope this helps :)