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qwelly [4]
3 years ago
10

Find the simple interest on $1500 for 5 years at 3.5%

Mathematics
2 answers:
antoniya [11.8K]3 years ago
3 0

Answer:

$1781.53

Step-by-step explanation:

Simple Interest Rate Formula: A = P(1 + r)ⁿ

Step 1: Define variables

Principle amount <em>P </em>= 1500

Rate <em>r</em> = 0.035

Years <em>n</em> = 5

Step 2: Substitute and Evaluate for A

A = 1500(1 + 0.035)⁵

A = 1500(1.035)⁵

A = 1500(1.18769)

A = 1781.53

Rama09 [41]3 years ago
3 0
I think the answer is $1781.53 :)
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stepan [7]

Answer : The correct options are:

DE + EF > DF

5 < DF < 13

Δ DEF is a scalene triangle.

Step-by-step explanation :

As we know that there are three types of triangle.

(1) Equilateral triangle : It is a triangle in which the three sides and angle are equal.

(2) Isosceles triangle : It is a triangle in which the two sides and two angle are equal.

(3) Scalene triangle : It is a triangle in which the three sides and angle are not equal.

Now we have to determine the length DF.

using Pythagoras theorem:

(Hypotenus)^2=(Perpendicular)^2+(Base)^2

(9)^2=(Perpendicular)^2+(4)^2

81=(Perpendicular)^2+16

(Perpendicular)^2=81-16

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Perpendicular=8.06

The length DF = 8.06 unit

So, we can say that:

DE + EF > DF

Hence, from the given options we conclude that, the correct options are:

DE + EF > DF

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8 0
3 years ago
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2 years ago
According to a​ survey, 60 ​% of the residents of a city oppose a downtown casino. Of these 60 ​% about 8 out of 10 strongly opp
katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

Step-by-step explanation:

​(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino. ​

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

  • Probability that a radomly selected resident opposes the casino: P(A)

  • Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the <em>probability that a radomly selected resident opposes the casino</em>, P(A)

Probability = number of favorable outcomes / number of possible outcomes

  • P(A) is <em>given as 60%</em>, which in decimal form is 0.60

ii) Next, determine,the <em>probability that a resident who opposes the casino strongly opposes it</em>, P(B/A):

  • It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or  intersection: P(A∩B).

So, you can use the definition of conditional probability:

  • P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

  • P(A∩B) = P(B/A)×P(A) =  (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that <em>a radomly selected resident who opposes the casino does strongly oppose the casino</em>, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

​(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the​ casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

8 0
3 years ago
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