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xenn [34]
3 years ago
5

A model house is built on a base then measures 9 1/4 inch. Wide and 8 4/5 inch. Long. What is the total area of the model house'

s base
Mathematics
1 answer:
Mrac [35]3 years ago
6 0
The total area would be 9 1/4 multiplied by 8 4/5 which would equal 81.4 inches
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Answer & explanation please..30 points?​
inn [45]

Looks like 75%. Not sure what they're talking about for the reduce part.

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3 years ago
Pleae answer this fast asap
BARSIC [14]

Answer:

I think its (2, 1) .

Step-by-step explanation:

the 2 represents the x axis

the 1 represents the y axis

7 0
3 years ago
About 60% of people in North America know how to swim. Use that statistic to answer the questions below.
kenny6666 [7]

Answer:

(Picture)

Step-by-step explanation:

To find 60% of people you just multiply .6 with the number you are trying to find 60% of. Like 100. 100 times .6 = 60.

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Read 2 more answers
Thanks for helping, I really appreciate it
den301095 [7]

Answer:

a)ΔFHA is similar to ΔZIA by hypotenuse side test.

reason:- angle H and angle I are of 90 degrees.

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angle F = angle Z, angle H = angle I , angle angle A = angle A

The scale factor is 3/2......( HA/IA = 12/8 = 3/2)

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7 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

x^3y'' + 2x^2y' + 4y

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ;  x=x_o is  located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0

y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0

The standard form of the differential equation is :

\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0

Thus;

P(x) = \dfrac{2}{x}

Q(x) = \dfrac{4}{x^3}

The zeros of x,x^3  is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x)    and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = x*\dfrac{2}{x}

p(x) = 2

q(x) = x²Q(x)

q(x) = x^2 * \dfrac{4}{x^3}

q(x) =\dfrac{4}{x}

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic  at x = 0

Q(x) = \dfrac{4}{x^3}  do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0
3 years ago
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