The expressions equivalent to -0.5(1.7+1.7) are -0.5(1.7) - 0.5(1.7)
and 2(-0.5(1.7))
<h3>Distributive law of expansion</h3>
Given the expression below;
-0.5 (1.7 + 1.7)
According to the distributive law;
A(B+C) = AB + AC
Expand
-0.5(1.7) + (-0.5)(1.7)
-0.5(1.7) - 0.5(1.7)
2(-0.5(1.7))
Hence the expressions equivalent to -0.5(1.7+1.7) are -0.5(1.7) - 0.5(1.7)
and 2(-0.5(1.7))
Learn more on distributive law here: brainly.com/question/25224410
#SPJ1
The answer is n=10 I already did this
The correct answer is Zero
Let x be the number of $10 bills in Iago pocket.
1. If he has twice as many $1 bills as $10 bills, then he has (2x) $1 bills.
2. He has two fewer $20 bills than he does $10 bills, then he has (x-2) $20 bills.
3. He has three more $5 bills than $10 bills, then he has (x+3) $5 bills.
In total he has $160 that is x·10+2x·1+(x-2)·20+(x+3)·5.
Equate these two expressions and solve the equation:

Thus, he has
- 5 bills for $10;
- 10 bills for $1;
- 3 bills for $20;
- 8 bills for $5.
According to the characteristics of <em>ticket</em> sales and the resulting system of linear equations we find that 122 children bought each one a ticket on Sunday.
<h3>How many children went to the movie theatre?</h3>
In this question we have a <em>word</em> problem, whose information must be translated into <em>algebraic</em> expressions to find a solution. Let be x and y the number of children and adults that went to the movie theatre, respectively.
We need two <em>linear</em> equations, one for the number of people assisting to the theatre and another for the total sales:
x - 4 · y = 0 (1)
6.30 · x + 9.50 · y = 1063.20 (2)
By algebraic procedures the solution to this system is: x = 122.559, y = 30.639. Since the number of tickets sold are integers, then we truncate each result: x = 122, y = 30.
According to the characteristics of <em>ticket</em> sales and the resulting system of linear equations we find that 122 children bought each one a ticket on Sunday.
To learn on systems of linear equations: brainly.com/question/27664510
#SPJ1