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devlian [24]
3 years ago
9

Find the total volume of this composite figure.

Mathematics
1 answer:
UNO [17]3 years ago
3 0

Answer:

volume = 76 ft³

Step-by-step explanation:

(6 x 3 x 2) + (5 x 4 x 2) = 36 + 40 = 76 ft³

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Please find solution in the picture attached

Step-by-step explanation:

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Simplify 2^3 • 2^7<br><br> answer quick pls lol
yarga [219]

Answer:

It's A.

Step-by-step explanation:

2^3 •2^7 = 1024

2^10 = 1024

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EASY BUNCH OF POINTS &amp; WILL GIVE BRAINLIEST:) Find the distance FG between the points F(2,7) and G(4, -1). Round your answer
FrozenT [24]

Answer:

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

Use following formulas to determine volumes of sphere and cylinder:

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

Then

Answer 2: correct choice is D.

Step-by-step explanation:

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3 years ago
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a turtle and a snail are 360 meters apart, and they start to move toward each other at 3 pm. if the turtle is 11 times as fast a
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The Highway Safety Department wants to study the driving habits of individuals. A sample of 32 cars traveling on the highway rev
GarryVolchara [31]

Answer:

n=126

Step-by-step explanation:

Data given and previous concepts

\bar X=60 represent the sample mean

s=11 represent the sample deviation

n=32 represent the sample size

Confidence =0.95 or 95%

\alpha =1-0.95=0.05 represent the significance level

ME= 2 represent the margin of error required

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma)

Solution to the problem

Since we don't have the population deviation. We know that the margin of error for a confidence interval is given by:

Me=t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The next step would be find the value of \t_{\alpha/2}, \alpha=1-0.95=0.05 and \alpha/2=0.025. The degrees of freedom are given by:

df=n-1=32-1=31

Using the normal standard table, excel or a calculator we see that:

t_{\alpha/2}=2.04

And the code in excel is this one:  "=T.INV(1-0.025,31)"

If we solve for n from formula (1) we got:

\sqrt{n}=\frac{t_{\alpha/2} s}{Me}

n=(\frac{t_{\alpha/2} s}{Me})^2

And we have everything to replace into the formula:

n=(\frac{2.04(11)}{2})^2 =125.88

And if we round up the answer we see that the value of n to ensure the margin of error required \pm=2 miles is n=126.

3 0
3 years ago
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