Answer: 1 van can hold 18 people, and 1 bus can hold 53 people.
What we know: Class A rented 2 filled vans and 7 buses with 407 students.
Class B rented and filled 1 van and 7 buses with 389 students.
What we need to know: How many students can a van carry? How many students can a bus carry?
Equation A: 2v + 7b = 407
Equation B: 1v + 7b = 389
Variables used: v = amount of people that can fill a van and b = amount of people that can fill a bus
This is quite a simple equation, because we know that class A used 1 more van than Class B, and the question says that each vehicle was full. So, all you have to do it subtract 389 from 407 to get 18. That means that 1 can can hold 18 people.
Now you just plug it in to find the value for b, 1(18) + 7b = 389
7b = 371
b = 53
So the amount of people that can fit on a van is 18, and the amount of people that can ft on a bus is 53.
Answer:
2+2 is 4 minus 1 is 3.
Step-by-step explanation:
Think about the question, you can't say that i am wong.
Answer:
Distance between fence and diagonal piece = 7.48 feet (Approx.)
Step-by-step explanation:
Given:
Vertical fence height = 5 feet
Length of diagonal piece = 9 feet
Find:
Distance between fence and diagonal piece
Computation:
Using trigonometry theorem;
Base = √Hypotenuse² - Perpendicular²
Distance between fence and diagonal piece = √Length of diagonal piece² - Vertical fence height²
Distance between fence and diagonal piece = √9² - 5²
Distance between fence and diagonal piece = √81 - 25
Distance between fence and diagonal piece = √56
Distance between fence and diagonal piece = 7.48 feet (Approx.)
Step-by-step explanation:
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Answer:
$31,045.50
Step-by-step explanation:
Revenue from sales = ($855/item)p
Expenses: $6,780
Revenue if p = 250 is R(250) = ($855/item)(250 items) = $213,750
Subtracting expenses, we get a profit of $206,970.
The CEO of the company earns 15% of this profit, or:
0.15($206,970) = $31,045.50
