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2 years ago

PLEASE HELP ASSP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Lynna [10]2 years ago

6 0

Answer:

Step-by-step explanation:

The original equation is cos 64 = 32/k. To solve for k we need to isolate it. we can multiply by k then divide by cos 64. This gives us the equation k = 32/cos 64. Therefore, B is the right answer.

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On a coordinate plane, a curved line crosses the x-axis at (negative 1, 0) and the y-axis at (0, 2).

telo118 [61]

Answer:

Step-by-step explanation: the answer is you 0,7

4 0

3 years ago

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In ∆MNP, m∠N = 90º, NH – altitude, m∠P = 21º, PM = 4 cm. Find MH.

Sveta_85 [38]

Answer:

0.51 cm

Step-by-step explanation:

In right triangle MNP, MP = 4 cm, m∠N = 90°, m∠P = 21°

By the sine definition,

$\sin \angle P=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{MN}{MP}\\ \\MN=MP\sin \angle P\\ \\MN=4\sin 21^{\circ}\approx 1.43\ cm$

Now, consider right triangle HMN (it is right because NH is an altitude). By the cosine definition,

$\cos \angle M=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{MH}{MN}\\ \\MH=MN\cos \angle M$

In the right triangle, two acute angles are always complementary, so

$m\angle M=90^{\circ}-m\angle P=90^{\circ}-21^{\circ}=69^{\circ}$

Thus,

$MH=1.43\cos 69^{\circ}\approx 0.51\ cm$

7 0

2 years ago

I need health drink is 130% of the recommended daily allowance RDA for a certain vitamin the RDA for this vitamin is 45 MG. How

Tanzania [10]

From this question I take it that you need to know what is 130% of 45 mg. 130% of 45 is equal to 1.3x45, which is 58.3. So, your answer is 58.3 mg of the vitamin.

5 0

2 years ago

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The radius of the circle is increasing at a rate of 2 meters per minute and the sides of the square are increasing at a rate of

Lunna [17]

Answer:

Change in area=24 $\pi$ -48

Step-by-step explanation:

Let s will be the side of square and r will be the radius of circle.

Then two given conditions are

1)dr/dt=2 m/s

2)ds/dt=1 m/s

Area enclosed=(Area of square)-(Area of circle)

Area of square= $s^{2}$

Area of circle= $\pi r^{2}$

Area enclosed= $(\pi r^{2})-s^{2}$

dA/dt=2 $\pi$ r(dr/dt)-2s(ds/dt)

At s=24,and r=6

dA/dt=2( $\pi$ )(6)(2)-2(24)(1)

Change in area=24 $\pi$ -48

6 0

2 years ago

The medians $AD$, $BE$, and $CF$ of triangle $ABC$ intersect at the centroid $G$. The line through $G$ that is parallel to $BC$

Flauer [41]

G divides each median in the ratio of 2 to 1 (the longer side goes from G to the angle) triangle AMN is similar to triangle ABC (why?) AMN is a scaled version of ABC (by a factor of ⅔) its area should be scaled by (⅔)^2

6 0

3 years ago