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pickupchik [31]
3 years ago
15

HELP ASAP ILL GIVE You 5 stars What is the solution to this inequality? 7x + 25<=11

Mathematics
2 answers:
Elan Coil [88]3 years ago
4 0

Answer: Inequality form: x<=-2

Interval notation: (-infinity,-2]

JulsSmile [24]3 years ago
3 0

Answer:

Step-by-step explanation:

smplifying

7x + 11 = 25

Reorder the terms:

11 + 7x = 25

Solving

11 + 7x = 25

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-11' to each side of the equation.

11 + -11 + 7x = 25 + -11

Combine like terms: 11 + -11 = 0

0 + 7x = 25 + -11

7x = 25 + -11

Combine like terms: 25 + -11 = 14

7x = 14

Divide each side by '7'.

x = 2

Simplifying

x = 2

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If DE=4x+10, EF =2x-1, and DF=9x-15, find DF
svetoff [14.1K]

Answer:


Step-by-step explanation:

If DE = 4x+10,EF =2X -1, and DF= 9x - 15 find DF

(de + ef ) - df = 2e || 2e/2 = e || ed - e = d || ef - e = f || f + d =  df

de + ef = 6x + 11 || (6x +11) - df = -3x -6 || 2e/2 = -3x/2 - 3  || (-3x/2 - 3) - de = x/2 + 7||  (- 3x/2 - 3) - ef = -x/2 - 1|| d + f = 6


7 0
3 years ago
Read 2 more answers
2.38 Baggage fees: An airline charges the following baggage fees: $25 for the first bag and $30 for the second. Suppose 54% of p
Anna71 [15]

The average baggage-related revenue per passenger is $16.30 per passenger.

<h3>Expected value</h3>

Expected value formula: x×p(x)

First step

No passenger=0×.54

No passenger=0

Second step

One checked luggage for first bag=.30×$25

One  checked luggage for first bag=$7.50

Third step

Two piece  for the first and second bag=.16×($25+$30)

Two piece  for the first and second bag=.16×$55

Two piece  for the first and second bag=$8.80

Last step

Expected value=$7.50+$8.80

Expected value=$16.30

Therefore the average baggage-related revenue per passenger is $16.30 per passenger.

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7 0
2 years ago
How many palimdromic numbers is there between 300 and 400
blagie [28]

A palindrome is something that reads the same forwards and backwards.

If the number is a palindrome and it's between 300 and 400, then the
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So all we have left to fill in is the digit in the middle.

There are 10 possibilities for that one ... the digits ' 0 ' through ' 9 '.

So there are <em>10</em> palindromic numbers between 300 and 400.


8 0
3 years ago
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Let the "number" be n.

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one day shahed was playing with numbers.He wrote 15 fractions using all natural numbers from 1 to 30 exactly once-either as nume
dusya [7]

Answer:

15

Step-by-step explanation:

half of 30 is 15

he used all the numbers upto 30 once

all the numbers in between arent integers but decimals

8 0
3 years ago
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