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ladessa [460]
4 years ago
14

12,20,28,36 are all multiples of 1, 2 and what?

Mathematics
2 answers:
liberstina [14]4 years ago
4 0

1) one is multiple of all positive integers. So, yes it is multiple of all that numbers.

2) Two is multiple for all those number which has even digit in unit place. So, yes they all are multiple of 2 too.

mariarad [96]4 years ago
4 0
4 is also a multiple of 12 20 28 36 :P
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When you divide the number of permutations of 11 objects taken 3 at a time by​ 3!, you will get the number of combinations of 11
Sloan [31]

Answer:

Yes

Step-by-step explanation:

Permutation :

nPr = n! ÷ (n - r)!

nCr = n! ÷ (n-r)!r!

11 objects taken 3 at a time :

11P3 = 11! ÷ (11 - 3)!

11P3 = 11! / 8!

11P3 = (11 * 10 * 9 )

11P3 = 990

Dividing by 3!

3! = 3*2*1 = 6

= 990 / 6

= 165

For combination :

11C3 = 11! ÷ 8!3!

11C3 = (11 * 10 * 9) / (3 * 2 * 1)

11C3 = 990 / 6

11C3

4 0
3 years ago
Two students from a group of eight boys and 12 girls are sent to represent the school in a parade. If the students are chosen at
kari74 [83]

Answer:

Step-by-step explanation:

* Lets explain how to find the probability of an event  

- The probability of an Event = Number of favorable outcomes ÷ Total

 number of possible outcomes

- P(A) = n(E) ÷ n(S) , where

# P(A) means finding the probability of an event A  

# n(E) means the number of favorable outcomes of an event

# n(S) means set of all possible outcomes of an event

- Probability of event not happened = 1 - P(A)

- P(A and B) = P(A) . P(B)

* Lets solve the problem

- There is a group of students

- There are 8 boys and 12 girls in the group

∴ There are 8 + 12 = 20 students in the group

- The students are sent to represent the school in a parade

- Two students are chosen at random

∴ P(S) = 20

- The students that chosen are not both girls

∴ The probability of not girls = 1 - P(girls)

∵ The were 20 students in the group

∵ The number of girls in the group was 12

∴ The probability of chosen a first girl = 12/20

∵ One girl was chosen, then the number of girls for the second

  choice is less by 1 and the total also less by 1

∴ The were 19 students in the group

∵ The number of girls in the group was 11

∴ The probability of chosen a second girl = 11/19

- The probability of both girls is P(1st girle) . P(2nd girl)

∴ The probability of both girls = (12/20) × (11/19) = 33/95

- To find the probability of both not girls is 1 - P(both girls)

∴ P(not both girls) = 1 - (33/95) = 62/95

* The probability that the students chosen are not both girls is 62/95

3 0
3 years ago
Read 2 more answers
The length of a rectangle is (x+5)cm the width is 5x write an exspresion for the perimiter of the rectangle
den301095 [7]
Perimeter = 2(width) + 2(length)
w = 5x
l = x + 5

P = 2(5x) + 2(x + 5)
P = 10x + 2x + 10
P = 12x + 10
6 0
3 years ago
What line represents tereasas statement
lys-0071 [83]
Line A is the correct answer because the line crosses the 7 dish point at the one minute point
7 0
3 years ago
The perimeter of sasquare is 20 ft. If you increase the length of the square by 2 feet and decrease the width by 1 foot what is
ElenaW [278]
Perimeter of a square = 4s = 20ft
s = 20/4 = 5 feet

New length = 5 + 2 = 7 ft
New width = 5 - 1 = 4ft
New perimeter = 2(7 + 4) = 2(11) = 22ft
7 0
3 years ago
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