STEP 1:
BAGS OF FOUR
find number of bags needed to total 74 apples
= 74 ÷ 4 apples/bag
= 18.5 bags
*must round up to 19 bags because we cannot buy a partial bag
STEP 2:
BAGS OF FOUR
calculate price of 19 bags of 4 apples per bag
= 19 bags * $5/bag
= $95 for 19 bags of 4 apples/bag
STEP 3:
BAGS OF SIX
find number of bags needed to total 74 apples
= 74 ÷ 6 apples per bag
= 12.3333 bags needed
*must round up to 13 bags because we cannot buy a partial bag
STEP 4:
BAGS OF SIX
calculate price of 13 bags of 6 apples per bag
= 13 bags * $7 per bag
= $91 for 13 bags of 6 apples/bag
ANSWER: The smallest cost to buy 74 apples is $91.
Hope this helps! :)
It's a probability problem to find the odds of picking a green or red
shirt out of the 10 shirts on Thursday, Friday and Saturday since you
have randomly already know you have picked a blue shirt on the other
days. Not sure if you have this as a multiple question problem as you didn't list any possible answers (A. 7/20, B. 5/47, C. 2/5, D. 4/125) to the question. A, B, C, D being like 7 chances out of 20, 5 chances out 47, 2 chances out of chances 5 or 4 chances out of 125 (example answers only).
Probability = Number favorable outcomes / total number of outcomes
Answer:
both of them are odd (because both of them are even, the reverse would be true)
Step-by-step explanation:
if she worked 8 on Monday, and on Wednesday worked for 3/4ths that amount of time she would've worked 6 hours. So an UNTRUE statement about this would be that they're both odd.
The original was expanded...
