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3 years ago

Solve for e E= mc2 m=3 c=6 what is the answer please

Mathematics

2 answers:

alina1380 [7]3 years ago

8 0

E=mc^2 if m=3 and c=6

e=3(6^2)

e=3(36)

e=108

irina1246 [14]3 years ago

5 0

E = mc^2
m = 3
c = 6
e = 3 (6^2)
e = 3 (36)
e = 108

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4n + 3 < 6n + 8 - 2n Pls solve in steps

murzikaleks [220]

Answer:

All real numbers would be the correct answer.

Step-by-step explanation:

First of all, add 6n to -2n which now the equation would be 4n+3 < 4n+8.

Now, subtract 4n to both sides and subtract 3 to both sides. Now you will have 0n < 5 which will be all real numbers.

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3 years ago

BRAINLIEST, URGENT

stira [4]

Answer:

12.5 m

Step-by-step explanation:

1st drop 50 m

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2 years ago

PLEASE HELP NEED HELP ASAP!!!!!!

Nataly_w [17]

Answers:

x = 3

y = 9

=========================================================

Explanation:

We're told that angle A is 20x. The diagram shows we have an equilateral triangle (since all three sides are the same length), so we know that all angles are the same measure and they are equal to 60 degrees.

Equate 20x and 60. So we solve 20x = 60 and that leads to x = 3 after you divide both sides by 20.

Since we have a triangle with all sides equal, we know that AB = AC = 9, therefore y = 9 because y is the length of AB.

5 0

3 years ago

Read 2 more answers

Cona has 42mats. dillin has 27mats. what does cona have then dillin

DaniilM [7]

The answer is 15 because you subtract 42 and 27

8 0

3 years ago

Which side lengths form a right triangle? Choose all answers that apply: Choose all answers that apply: (Choice A) A 3, 6, \sqrt

dlinn [17]

Answer:

A, B and C

Step-by-step explanation:

Given any three side lengths of a right triangle, the longest side is the hypotenuse.

The side lengths of a right triangle must satisfy the Pythagorean Theorem.

Pythagorean Theorem: $Hypotenuse^2=Opposite^2+Adjacent^2$

Option A: $3, 6, \sqrt{45}$

$(\sqrt{45})^2=3^2+6^2\\45=36+9\\45=45$

True

Option B: 2.5, 6, 6.5

$6.5^2=6^2+2.5^2\\42.25=36+6.25\\42.25=42.25 (TRUE)$

Option C: $4, 8, \sqrt{80}$

$4, 8, \sqrt{80}\\( \sqrt{80})^2=4^2+8^2\\80=16+64\\80=80 (TRUE)$

Since all are true, the side lengths in Options A, B and C forms a right triangle,

4 0

3 years ago