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goldfiish [28.3K]
3 years ago
10

Solve for e E= mc2 m=3 c=6 what is the answer please

Mathematics
2 answers:
alina1380 [7]3 years ago
8 0
E=mc^2 if m=3 and c=6

e=3(6^2)

e=3(36)

e=108
irina1246 [14]3 years ago
5 0
E = mc^2
m = 3
c = 6
e = 3 (6^2)
e = 3 (36)
e = 108
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PLEASE HELP AND SHOW WORK!!
Nastasia [14]

Answer:

Pipe 1 alone fills a tank in 10 min

Pipe 2 alone fills the tank in 20 min

If both are turned on together, how long will it take to fill the tank???

Pipe 1 fills at the RATE of 1/10th tank per min

Pipe 2 fills at the RATE of 1/20th tank per min

Pipe 1 + Pipe 2 fills at the rate of 1/10+1/20 or 3/20th tank per min

Let x= time to fill the tank

(3/20)(x)=1 Where 1 denotes a full tank (Multiply both sides by 20)

3x=20

x=6 2/3 min----------both working together

NOW YOUR PROBLEM

Let x= amount of time for smaller pipe to fill the tank

Then (x-5)=amount of time for larger pipe to fill the tank

NOW HERE'S WHERE THE RECIPROCAL COMES IN:

The smaller pipe fills the tank at the RATE of 1/x cu units per min

The larger tank fills the tank at the RATE of 1/(x-5) cu units per min

Together, they fill the tank at the rate of 1/x+(1/(x-5)) cu units per min

But now we are told that together the fill the tank in 11 1/9 minutes. so our equation to solve is:

(1/x+(1/(x-5))(11 1/9)=1 where 1 denotes a full tank. In fact, in each of the above reciprocals, the 1 denotes a full tank.

So, dividing both sides by 11 1/9, we get:

1/x+(1/(x-5)=1/(11 1/9)-------------- which is your equation

I assume that you have no problems solviing this eq.

Hope this helps----ptaylor

Step-by-step explanation:

7 0
2 years ago
PLLLZZ EXPLAIN HOW YOU GOT IT! I will give you branilest!
Nezavi [6.7K]

Answer:

Getting through ratio method

100-20=80 percent have to pay

18:80

<em>x</em>:100

cross multiply

80 x <em>x=1</em>8 x 100

80x=1800

x=1800/80

x=22.5

So the original price was $22.50

Step-by-step explanation:

5 0
2 years ago
using the associative property, 9 + (6 - 3) = (9 + 6) + 3. is 9 - (6 - 3) equal to (9 - 6) - 3? explain.
goldfiish [28.3K]
No because it only works with addition and multiplication

9+(-6-3)=(9-6)-3 is true tho



9-(6-3)=9-(3)=6
(9-6)-3=(3)-3=0
so not equivilent
4 0
3 years ago
What fraction is equal to 4.5
pantera1 [17]

Answer:

9/2

Step-by-step explanation:

in order to find the fraction form of 4.5... we need to set a denominator. The denominator has to be greater than 1 because we 4.5 is not a whole number...

we want the simplest denominator in the end... so we'll pick 2 for a denominator and change it if it doesn't work in the end...

now that we know the denominator... we have to make the numerator 4 times larger than the denominator (2)... when we do this... we get 8/2

since we made the numerator 4 times larger than the denominator... we know that 8/2 is the same as 4

now we need to find the remaining 1/2

this can be done by simply adding 1/2 to 8/2 (which is easily done thanks to a common denominator)

Since 9/2 cannot be simplified any further... it is our final answer

4 0
2 years ago
Match the identities to their values taking these conditions into consideration sinx=sqrt2 /2 cosy=-1/2 angle x is in the first
BaLLatris [955]

Answer:

\cos(x+y) goes with -\frac{\sqrt{6}+\sqrt{2}}{4}

\sin(x+y) goes with \frac{\sqrt{6}-\sqrt{2}}{4}

\tan(x+y) goes with \sqrt{3}-2

Step-by-step explanation:

\cos(x+y)

\cos(x)\cos(y)-\sin(x)\sin(y) by the addition identity for cosine.

We are given:

\sin(x)=\frac{\sqrt{2}}{2} which if we look at the unit circle we should see

\cos(x)=\frac{\sqrt{2}}{2}.

We are also given:

\cos(y)=\frac{-1}{2} which if we look the unit circle we should see

\sin(y)=\frac{\sqrt{3}}{2}.

Apply both of these given to:

\cos(x+y)

\cos(x)\cos(y)-\sin(x)\sin(y) by the addition identity for cosine.

\frac{\sqrt{2}}{2}\frac{-1}{2}-\frac{\sqrt{2}}{2}\frac{\sqrt{3}}{2}

\frac{-\sqrt{2}}{4}-\frac{\sqrt{6}}{4}

\frac{-\sqrt{2}-\sqrt{6}}{4}

-\frac{\sqrt{6}+\sqrt{2}}{4}

Apply both of the givens to:

\sin(x+y)

\sin(x)\cos(y)+\sin(y)\cos(x) by addition identity for sine.

\frac{\sqrt{2}}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{2}}{2}

\frac{-\sqrt{2}+\sqrt{6}}{4}

\frac{\sqrt{6}-\sqrt{2}}{4}

Now I'm going to apply what 2 things we got previously to:

\tan(x+y)

\frac{\sin(x+y)}{\cos(x+y)} by quotient identity for tangent

\frac{\sqrt{6}-\sqrt{2}}{-(\sqrt{6}+\sqrt{2})}

-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}

Multiply top and bottom by bottom's conjugate.

When you multiply conjugates you just have to multiply first and last.

That is if you have something like (a-b)(a+b) then this is equal to a^2-b^2.

-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}} \cdot \frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}-\sqrt{2}}

-\frac{6-\sqrt{2}\sqrt{6}-\sqrt{2}\sqrt{6}+2}{6-2}

-\frac{8-2\sqrt{12}}{4}

There is a perfect square in 12, 4.

-\frac{8-2\sqrt{4}\sqrt{3}}{4}

-\frac{8-2(2)\sqrt{3}}{4}

-\frac{8-4\sqrt{3}}{4}

Divide top and bottom by 4 to reduce fraction:

-\frac{2-\sqrt{3}}{1}

-(2-\sqrt{3})

Distribute:

\sqrt{3}-2

6 0
2 years ago
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