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pogonyaev
3 years ago
10

Can you guys help we with this question. ​​​​​​

Mathematics
2 answers:
Natasha2012 [34]3 years ago
6 0
4r-2n=2

4r-10=2

4r=12

R=13
satela [25.4K]3 years ago
4 0

Answer:

40

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2

= (4x^2-1/4(x)^2)^5

now

x =4x^2. ,a = 1/4(x)^2 ,n =5

we have

general term = Cr *x^r *a^(n-r)

= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)

= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)

= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)

= Cr * 4(2r-n) *x(4r-2n)

now for x^2

4r-2n = 2

4r -10=2

4r =12

r = 3

now for coeff

C(5,3) * 4^(2*3-5)

5!/(3!*(5-3)!) * 4

5*4/(2*1)*4

40

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PLS ANSWER THE BELOW QUESTION AND I'LL MARK U AS BRAINLIST
MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

a) \dfrac{3x}{2}-5=4

Add 5 to both sides

\dfrac{3x}{2}-5 +5 = 4 + 5\\\\\dfrac{3x}{2} = 9 \\\\Now \ multiply \ both \ sides  \ by  \  2 \\\\\dfrac{3x}{2}*2 = 9*2\\\\3x = 18\\Now \ divide \ both \ sides  \ by \ 3\\\\x =\dfrac{18}{3}\\\\

x = 6

b) \dfrac{x-3}{5} + 1 = -2\\\\\\Subtract \ 1 \ from  \ both \ sides\\\\\dfrac{x-3}{5} = -2 -1\\\\\dfrac{x-3}{5} = -3\\\\Multiply \ both \ side \ by \ 5\\\\x - 3 = -3*5\\\\x -3 = -15\\\\

Add 3 to both sides

x = -15 +3

x = -12

7 0
3 years ago
Read 2 more answers
What is the product of two integers that equal -21
earnstyle [38]

This is the answer 7 x -3


7 x -3 = -21

8 0
3 years ago
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Line segment AB has endpoints A(1,8) and B(7,−4). What are the coordinates of the point located 5/6 of the way from A to B?
const2013 [10]

The coordinate of the point is (6,-2)

<h3>How to determine the coordinate of the point?</h3>

The given parameters are:

A = (1,8)

B = (7,-4)

The location of the point (i.e 5/6) means that the ratio is:

m :n = 5 : (6 - 5)

m : n = 5 : 1

The coordinate of the point is then calculated as:

(x,y) = \frac{1}{m + n}* (mx_2 + nx_1,my_2 + ny_1)

So, we have:

(x,y) = \frac{1}{5 + 1}* (5 * 7 + 1 * 1 , 5 * -4 + 1 * 8)

Evaluate

(x,y) = \frac{1}{6}* (36 , -12)

Evaluate the product

(x,y) = (6,-2)

Hence, the coordinate of the point is (6,-2)

Read more abut line segment ratio at:

brainly.com/question/12959377

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6 0
2 years ago
What is an equation of the line that passes through the points (4,-1) and (8,5)?
fiasKO [112]

Answer:

y=3/2x-7

Step-by-step explanation:

the equation of the line for slope-intercept form is y=mx+b, where  m is the slope and b is the y intercept.

we are given two points: (4,-1) and (8,5)

the equation for slope is (y2-y1)/(x2-x1)

label the points:

x1=4

y1=-1

x2=8

y2=5

now substitute into the equation:

m=(5--1)/(8-4)

m=6/4

m=3/2

the slope of the line is 3/2

here is our equation so far:

y=3/2x+b

we need to find b

since the equation will pass through the points, we can substitute either one into the equation to find b

let's use (4,-1) as an example

substitute into the equation

-1=3/2(4)+b

-1=6+b

-7=b

the y intercept is -7

so the equation is y=3/2x-7

hope this helps!

8 0
3 years ago
Find all the missing elements:
pentagon [3]

Answer:

B = 34.2°

C = 58.2° or 121.8°

c= 10.6

Step-by-step explanation:

Step 1

Finding c

We calculate c using Pythagoras Theorem

c²= a² + b²

c = √a² + b²

a= 8, b = 7

c = √8² + 7²

c = √64 + 49

c = √(113)

c = 10.630145813

Approximately c = 10.6

Step 2

Find B

We solve this using Sine rule

a/sin A = b/sin B

A = 40°

a = 8

b = 7

Hence,

8/sin 40° = 7/sin B

8 × sin B = sin 40° × 7

sin B = sin 40° × 7/8

B = arc sin (sin 40° × 7/8)

B ≈34.22465°

Approximately = 34.2°

Step 3

We find C

Find B

We solve this using Sine rule

b/sin B = c/sin C

B = 34.2°

b = 7

c = 10.6

C = ?

Hence,

7/sin 34.2° = 10.6/sin C

7 × sin C = sin 34.2 × 10.6

sin C = sin 34.2° × 10.6/7

C = arc sin (sin 34.2° × 10.6/7)

C = arcsin(0.85)

C= 58.211669383

Approximately C = 58.2°

Or = 180 - 58.2

C = 121.8°

5 0
3 years ago
Read 2 more answers
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