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3 years ago

Can you guys help we with this question.

Mathematics

2 answers:

Natasha2012 [34]3 years ago

6 0

4r-2n=2

4r-10=2

4r=12

R=13

satela [25.4K]3 years ago

4 0

Answer:

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2

= (4x^2-1/4(x)^2)^5

now

x =4x^2. ,a = 1/4(x)^2 ,n =5

we have

general term = Cr *x^r *a^(n-r)

= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)

= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)

= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)

= Cr * 4(2r-n) *x(4r-2n)

now for x^2

4r-2n = 2

4r -10=2

4r =12

r = 3

now for coeff

C(5,3) * 4^(2*3-5)

5!/(3!*(5-3)!) * 4

5*4/(2*1)*4

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The area of a triangle is found using the formula Area = 1/2 x base x height.

Base = 8

Height = 18.

The area of 1 triangle = 1/2 x 8 x 18 = 72 square units.

There are a total of 4 sides, so total area = 72 x 4 = 288 units ^2

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3 years ago

Suppose the method of tree ring dating gave the following dates A.D. for an archaeological excavation site. Please show your wor

natita [175]

Answer:

a) $\bar X=\frac{1245+1245+1321+1191+1295+1330+1239+1250+1228}{9}= 1260.444$

b) $s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And if we replace we got:

$s = 45.580$

c) For this case since the sampel size is n=9 <30 we can use the t distribution in order to find the confidence interval.

d) $1260.444-2.306 \frac{45.580}{\sqrt{9}}= 1225.408$

$1260.444+2.306 \frac{45.580}{\sqrt{9}}= 1295.480$

Step-by-step explanation:

For this case we ave the following data:

1245 1245 1321 1191 1295 1330 1239 1250 1228

Part a

We can calculate the sample mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X= \frac{1245+1245+1321+1191+1295+1330+1239+1250+1228}{9}= 1260.444$

Part b

For this case we can use the following formula in order to find the sample standard deviation:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And if we replace we got:

$s = 45.580$

Part c

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

For this case since the sampel size is n=9 <30 we can use the t distribution in order to find the confidence interval.

Part d

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

We need to find the degrees of freedom given by:

$df = n-1 = 9-1=8$

Since the Confidence is 0.95 or 95%, the value of $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that $t_{\alpha/2}=2.306$

Now we have everything in order to replace into formula (1):

$1260.444-2.306 \frac{45.580}{\sqrt{9}}= 1225.408$

$1260.444+2.306 \frac{45.580}{\sqrt{9}}= 1295.480$

8 0

4 years ago

I need the answer to this

arlik [135]

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3 years ago

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Dmitrij [34]

Yes this is a function

The reason why is because the x coordinates do not repeat. Each x value maps to exactly one y value. For any input, there is exactly one output. If you were to graph all of these points, then the graph would pass the vertical line test.

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3 years ago

Read 2 more answers

You weigh a gallon of liquid in science class and learn that it is approximately 7.7 pounds. You pass the liquid to the next gro

IceJOKER [234]

Answer:

7.7 pounds = 3.5 kilograms

Step-by-step explanation:

Given that,

Weight of a gallon of liquid = 7.7 pounds

We need to find weight in kilograms.

We must know the relation between pounds and kilograms and it is as follows :

1 kilogram = 2.20 pounds

1 pounds = (1/2.2) kilograms

7.7 pounds = (7.7/2.2) kilograms

= 3.5 kilograms

Hence, 7.7 pounds is equal to 3.5 kilograms.

4 0

3 years ago

Can you guys help we with this question. ​​​​​​

Can you guys help we with this question.