Answer:
21 years old
Step-by-step explanation:
Anna = 5
You = 6 + (5)3
Equation =
(5)3 + 6
15 + 6 = 21
You are 21
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-Chetan K
Answer:
2
Step-by-step explanation:
The answer and work is in the SS below
D. because you have to get the price of the elastic, and ribbon and then add them together
Answer:
The standard deviation of weight for this species of cockroaches is 4.62.
Step-by-step explanation:
Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.
To find : What is the approximate standard deviation of weight for this species of cockroaches?
Solution :
We have given,
Mean ![\mu=50](https://tex.z-dn.net/?f=%5Cmu%3D50)
The sample mean x=55
A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.
i.e. P(X>55)=14%=0.14
The total probability needs to sum up to 1,
![P(X\leq 55)=1-P(X>55)](https://tex.z-dn.net/?f=P%28X%5Cleq%2055%29%3D1-P%28X%3E55%29)
![P(X\leq 55)=1-0.14](https://tex.z-dn.net/?f=P%28X%5Cleq%2055%29%3D1-0.14)
![P(X\leq 55)=0.86](https://tex.z-dn.net/?f=P%28X%5Cleq%2055%29%3D0.86)
The z-score value of 0.86 using z-score table is z=1.08.
Applying z-score formula,
![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Where,
is standard deviation
Substitute the values,
![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
![1.08=\frac{55-50}{\sigma}](https://tex.z-dn.net/?f=1.08%3D%5Cfrac%7B55-50%7D%7B%5Csigma%7D)
![1.08=\frac{5}{\sigma}](https://tex.z-dn.net/?f=1.08%3D%5Cfrac%7B5%7D%7B%5Csigma%7D)
![\sigma=\frac{5}{1.08}](https://tex.z-dn.net/?f=%5Csigma%3D%5Cfrac%7B5%7D%7B1.08%7D)
![\sigma=4.62](https://tex.z-dn.net/?f=%5Csigma%3D4.62)
The standard deviation of weight for this species of cockroaches is 4.62.