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bagirrra123 [75]
3 years ago
9

I need help! What is the solution to the equation?

Mathematics
1 answer:
Assoli18 [71]3 years ago
4 0
<h3>The value of x is 65</h3>

\displaystyle\tt\leadsto \sqrt[3]{x-1}=4

\displaystyle\tt\leadsto x-1 = 4^3

\displaystyle\tt\leadsto x = 4^3 + 1

\displaystyle\tt\leadsto x = 64 + 1

\displaystyle\leadsto \underline{\boxed{\textbf{\textsf{x = 65}}}}

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If we are going to write the equation in its mathematical form, we will see that it becomes,

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<em>I've attached a picture of a unit circle with the quadrant labeled. </em>

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Vsevolod [243]
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Hope this helps!! :) And the decimal is rounded, just so you know ;). If your teacher likes everything in simplest radical form, then just don't convert the 18*the square root of 2 into a decimal and solve as you normally would.





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