If x = 14, which equation is true?

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

7 0

Answer:

Is there a picture you can give us? I will try to answer it once you do! :)

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Given:

diamong [38]

Answer:

10-5 $\sqrt{2}$

Step-by-step explanation:

As per the attached figure, right angled $\triangle MDL$ has an inscribed circle whose center is $I$ .

We have joined the incenter $I$ to the vertices of the $\triangle MDL$ .

Sides MD and DL are equal because we are given that $\angle M = \angle L = 45 ^\circ.$

Formula for area of a $\triangle = \dfrac{1}{2} \times base \times height$

As per the figure attached, we are given that side a = 10.

Using pythagoras theorem, we can easily calculate that side ML = 10 $\sqrt{2}$

Points P,Q and R are at $90 ^\circ$ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of $\triangle$ MIL, $\triangle$ MID and $\triangle$ DIL.

Also,

$\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL$

$\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2$

So, radius of circle = $10-5\sqrt2$

8 0

3 years ago

Solve. x – 6 = –14 a. –20 b. 20 c. 8 d. –8

Nataliya [291]

If you would like to solve the equation x - 6 = - 14, you can calculate this using the following steps:

x - 6 = - 14
x = - 14 + 6
x = - 8

The correct result would be d. - 8.

5 0

3 years ago

Read 2 more answers

\large -\frac{2}{3}x+3=\frac{2}{3}x+\frac{1}{3}

german

Answer:

$\boxed {x = 2}$