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miss Akunina [59]
2 years ago
10

What is the solution set for 9x2-25 = 0?

Mathematics
1 answer:
Ronch [10]2 years ago
3 0

Answer:

I believe is A.

Step-by-step explanation:

9x^2 - 25 = 0

9x^2 = 25

x^2 = 25/9

x = 5/3

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Gerard bought 9 hamburgers and 3 orders of fries for 24.75. Chris bought 6 hamburgers and 4 orders of fries for 19.50. Each hamb
dezoksy [38]
<span>9 hamburgers and 3 fries for 24.75 and 6 hamburgers and 4 fries for 19.50 can be represented by 9h + 3f = 24.75 and 6h + 4f = 19.5 Multiply by 4 36h + 12f = 99 and multiply by -3 -18h -12f = -58.5 12f and -12f cancel each other out 36h - 18h = 99 -58.5 18h = 40.5 h = 2.25 hamburgers cost 2.25 9h + 3f = 24.75 9(2.25) + 3f = 24.75 3f = 24.75 - 20.25 = 4.50 f = 150 fries cost 1.50 One hamburger and one fries can be represented by : h + f 2.25 + 150 = 3.75</span>
8 0
3 years ago
Kameryn types 75 words per minute and is just starting to write a term paper. Joe already has 510 words written and types at a s
AnnZ [28]

Answer:

Kameryn will have more words typed than Joe when the number of minutes exceeds 34.

Step-by-step explanation:

Let

x -----> the number of minutes

y ----> the total words typed

we know that

<em>Kameryn</em>

y=75x -----> equation A

<em>Joe</em>

y=60x+510 -----> equation B

Solve the system of equations by substitution

Substitute equation A in equation B and solve for x

75x=60x+510

75x-60x=510

15x=510

x=34\ minutes

That means

For x=34 minutes

The amount of words written by Kameryn and Joe are the same.

therefore

For x > 34 minutes

Kameryn will have more words typed than Joe when the number of minutes exceeds 34.

6 0
3 years ago
Write the number equal to five tens and 13 ones
BigorU [14]

63     5*10=50  50+13=63  that is the answer  63
8 0
3 years ago
What is the problem of this solving?!
nika2105 [10]
     This question can be solved primarily by L'Hospital Rule and the Product Rule.

y= \lim_{x \to 0}  \frac{x^2cos(x)-sin^2(x)}{x^4}
 
     I) Product Rule and L'Hospital Rule:

y= \lim_{x \to 0} \frac{[2xcos(x)-x^2sin(x)]-2sin(x)cos(x)}{4x^3}
 
     II) Product Rule and L'Hospital Rule:

y= \lim_{x \to 0} \frac{[-2xsin(x)+2cos(x)]-[2xsin(x)+x^2cos(x)]-[2cos^2(x)-2sin^2(x)]}{12x^2} \\ y= \lim_{x \to 0} \frac{2cos(x)-4xsin(x)-x^2cos(x)-2cos^2(x)+2sin^2(x)}{12x^2}
 
     III) Product Rule and L'Hospital Rule:

]y= \alpha + \beta \\ \\ \alpha =\lim_{x \to 0} \frac{-2sin(x)-[4sin(x)+4xcos(x)]-[2xcos(x)-x^2sin(x)]}{24x} \\ \beta = \lim_{x \to 0} \frac{4sin(x)cos(x)+4sin(x)cos(x)}{24x} \\  \\ y = \lim_{x \to 0} \frac{-6sin(x)-4xcos(x)-2xcos(x)+x^2sin(x)+8sin(x)cos(x)}{24x}
 
     IV) Product Rule and L'Hospital Rule:

y = \phi + \varphi \\  \\ \phi = \lim_{x \to 0}  \frac{-6cos(x)-[-4xsin(x)+4cos(x)]-[2cos(x)-2xsin(x)]}{24x}  \\ \varphi = \lim_{x \to 0}  \frac{[2xsin(x)+x^2cos(x)]+[8cos^2(x)-8sin(x)]}{24x}
 
     V) Using the Definition of Limit:

y= \frac{-6*1-4*1-2*1+8*1^2}{24}  \\ y= \frac{-4}{24}  \\ \boxed {y= \frac{-1}{6} }
3 0
2 years ago
Which action will solve the equation?. m + 20 = 9. . Add 9 to each side.. Subtract 9 from each side.. Add 20 to each side.. Subt
Kruka [31]
M + 20 = 9
u need to subtract 20 from both sides because u want to isolate m

m + 20 = 9
m + 20 - 20 = 9 - 20
m = - 11
4 0
3 years ago
Read 2 more answers
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