To determine this, we need to set up fractional proportions.
First, put 12.5% (what we're looking for) over 100%, which is the total (256).
12.5/100 should be your first fraction.
Now, put x over 256, x being 12.5% of 256.
x/256 should be your second fraction.
Now put these two fractions as an equation.
x/256 = 12.5/100
This may be where things get tricky if you don't pay attention.
Cross multiply the top number (numerator) of x/256 with the bottom number (denominator) of 12.5/100.
You should end up with 100x.
Now, cross multiply the top number of 12.5/100 with the bottom number of x/256.
You should end up with 3200.
Now our equation is:
100x = 3200
Divide both sides by 100 to get x.
100x/100 = x
3200/100 = 32
x = 32 is now your simplified equation.
Your final answer is:
32 is 12.5% of 256.
Also, since 12.5% is 1/8 of 100%, we can test our answer.
Multiply 32 by 8 to get 8/8 (100%).
32 x 8 = 256.
Your answer is 32.
I hope this helps!

Factor the polynomial.
2(
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2(x-2)
Factor the other Polynomial.
3


This is your answer.

The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
Answer:

Step-by-step explanation:
we have


we know that
The function composition is equal to
(r ∘ s )(x) = r(s(x))
In the function r(x) substitute the variable x by the function s(x)
so

For x=3
substitute the value of x=3 in the function composition



