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ddd [48]
3 years ago
11

What number comes next in the series? 31, 1031, 402, 16, ____

Mathematics
1 answer:
spin [16.1K]3 years ago
4 0

Answer:

Another person already answered this question. Their name is writersparadise. I give all credit to him/her for this answer.

Step-by-step explanation:

There could be many answers for this question. In general, the number that comes after 16 is a number with 8 as the sum of its digits.

Explanation:

1st number 31 – Sum of digits is 3 + 1 = 4  

2nd number 1031 – Sum of digits is 1 + 0 + 3 + 1 = 5

3rd number 402 – Sum of digits is 4 + 0 + 2 = 6

4th number 16 – Sum of digits is 1 + 6 = 7

Therefore, the missing number could be the single digit number 8 or any of the two-digit numbers 17, 26, 35, 44, 53, 62, 71 or 80. It could also be a bigger number with the digits of any of the given two-digit numbers and 0 for the other digits such as 260 or 7001.

Read more on Brainly.in - https://brainly.in/question/3032926#readmore

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What is the equation of a vertical line passing through the point (-4, 7)?
MrRa [10]

Answer:

x=-4

Step-by-step explanation:

Since we know that the equation will be x= we will just have to take the x value of the coordinate point and that would be the x so in this case the x is -4 so the equation would be x=-4

8 0
3 years ago
Which transformation from the graph of a function f(x) describes the graph of g(x) =10f(x)
Elanso [62]
Multiplying a function by a constant factor (10 in this example) stretches the graph relative to the x-axis. If f(x) would be a sine, you would blow up the amplitude from -1..+1 to -10..+10.


8 0
3 years ago
A statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after
lana [24]

Answer:

95% confidence interval estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

(a) Lower Limit = 0.486

(b) Upper Limit = 0.624

Step-by-step explanation:

We are given that a statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after receiving their bachelor's.

She took a random sample of 200 graduates from the class of 1979 and determined their occupations in 1989. She found that 111 persons were still employed primarily as engineers.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

                         P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of persons who were still employed primarily as engineers  = \frac{111}{200} = 0.555

           n = sample of graduates = 200

           p = population proportion of engineers

<em>Here for constructing 95% confidence interval we have used One-sample z proportion test statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                 significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

 = [ 0.555-1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } } , 0.555+1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } } ]

 = [0.486 , 0.624]

Therefore, 95% confidence interval for the estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

7 0
3 years ago
Find the slope of line A2 B-2 C3 D-1
tatyana61 [14]

Answer:

-2

Step-by-step explanation:

The line is going down 2 over 1 making it -2/1

this becomes -2

5 0
3 years ago
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makvit [3.9K]
To start with, wee need to find the total number of candies in the bowl. 14+12+6=32. We then form a fraction based on the number of blue pieces and this number. 12/32. This is the probability of selecting a blue piece and converts into 37.5%
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