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3 years ago

14

The teacher spent 1/8 of the class period reviewing the answers to a worksheet. The class period was 1 1/2 hours length. How man

y minutes did the teacher spend reviewing the worksheet? Enter your response as a decimal.

1 answer:

Anestetic [448]3 years ago

4 0

Answer:

11 minutes and 15 seconds

Step-by-step explanation:

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Brainliest for best answer

Naily [24]

Answer:

Step-by-step explanation:

________

Good evening ,

_______________

-4x+3y=-12

-2x+3y=-18

This system is the same as

y = (4/3)x - 4

y = (2/3)x - 6

We note that the two coefficients 4/3 and 2/3 are positives

So the right answer is C (graph 2).

___

:)

3 0

4 years ago

Mera is making a food guide for health class. She needs the measurements of this picture to enlarge it for a poster. Remember to

astraxan [27]

Answer:

you gatta show the picture

Step-by-step explanation:

5 0

3 years ago

The function T(n) is defined below. Which of the following are equal to T(8)? Check all that apply. T(n) = 4n - 5

Klio2033 [76]

$T(n)=4n-5\\\\T(8)=4\cdot8-5=32-5=27\\\\T(5)+T(3)=4\cdot5-5+4\cdot3-5=20-5+12-5=22\neqT(8)\\\\T(7)+4=4\cdot7-5+4=28-5+4=27\\\\Answer:\\B.\ 27\\D.\ T(7)+4$

3 0

3 years ago

Can someone check whether its correct or no? this is supposed to be the steps in integration by parts

Gwar [14]

Answer:

$\displaystyle - \int \dfrac{\sin(2x)}{e^{2x}}\: \text{d}x=\dfrac{\sin(2x)}{4e^{2x}}+\dfrac{\cos(2x)}{4e^{2x}}+\text{C}$

Step-by-step explanation:

$\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}$

Given integral:

$\displaystyle -\int \dfrac{\sin(2x)}{e^{2x}}\:\text{d}x$

$\textsf{Rewrite }\dfrac{1}{e^{2x}} \textsf{ as }e^{-2x} \textsf{ and bring the negative inside the integral}:$

$\implies \displaystyle \int -e^{-2x}\sin(2x)\:\text{d}x$

Using <u>integration by parts</u>:

$\textsf{Let }\:u=\sin (2x) \implies \dfrac{\text{d}u}{\text{d}x}=2 \cos (2x)$

$\textsf{Let }\:\dfrac{\text{d}v}{\text{d}x}=-e^{-2x} \implies v=\dfrac{1}{2}e^{-2x}$

Therefore:

$\begin{aligned}\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x & =\dfrac{1}{2}e^{-2x}\sin (2x)- \int \dfrac{1}{2}e^{-2x} \cdot 2 \cos (2x)\:\text{d}x\\\\& =\dfrac{1}{2}e^{-2x}\sin (2x)- \int e^{-2x} \cos (2x)\:\text{d}x\end{aligned}$

$\displaystyle \textsf{For }\:-\int e^{-2x} \cos (2x)\:\text{d}x \quad \textsf{integrate by parts}:$

$\textsf{Let }\:u=\cos(2x) \implies \dfrac{\text{d}u}{\text{d}x}=-2 \sin(2x)$

$\textsf{Let }\:\dfrac{\text{d}v}{\text{d}x}=-e^{-2x} \implies v=\dfrac{1}{2}e^{-2x}$

$\begin{aligned}\implies \displaystyle -\int e^{-2x}\cos(2x)\:\text{d}x & =\dfrac{1}{2}e^{-2x}\cos(2x)- \int \dfrac{1}{2}e^{-2x} \cdot -2 \sin(2x)\:\text{d}x\\\\& =\dfrac{1}{2}e^{-2x}\cos(2x)+ \int e^{-2x} \sin(2x)\:\text{d}x\end{aligned}$

Therefore:

$\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{2}e^{-2x}\sin (2x) +\dfrac{1}{2}e^{-2x}\cos(2x)+ \int e^{-2x} \sin(2x)\:\text{d}x$

$\textsf{Subtract }\: \displaystyle \int e^{-2x}\sin(2x)\:\text{d}x \quad \textsf{from both sides and add the constant C}:$

$\implies \displaystyle -2\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{2}e^{-2x}\sin (2x) +\dfrac{1}{2}e^{-2x}\cos(2x)+\text{C}$

Divide both sides by 2:

$\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{4}e^{-2x}\sin (2x) +\dfrac{1}{4}e^{-2x}\cos(2x)+\text{C}$

Rewrite in the same format as the given integral:

$\displaystyle \implies - \int \dfrac{\sin(2x)}{e^{2x}}\: \text{d}x=\dfrac{\sin(2x)}{4e^{2x}}+\dfrac{\cos(2x)}{4e^{2x}}+\text{C}$

5 0

2 years ago

the angle of depression from an airplane at an altitude of 8000 feet to the airport is 7 degrees. Find the direct distance from

Aleks [24]

Answer:

direct distance = 65,644.07 feet

horizontal distance = 65,154.77 feet

Step-by-step explanation:

The angle of depression is the angle that the airplane does with the horizontal plane.

So, if this angle is 7° and the airplane is at an altitude if 8000 feet, we can find the direct distance and the horizontal distance using the tangent and the sine relations of the angle.

In the tangent of the angle, the opposite side will be the height of the airplane, and the adjacent side will be the horizontal distance (hd), so:

tangent(7) = 8000 / hd

hd = 8000 / tangent(7) = 65,154.77 feet

In the sine of the angle, the opposite side will be the height of the airplane, and the hypotenusa will be the direct distance (d), so:

sine(7) = 8000 / d

d = 8000 / sine(7) = 65,644.07 feet

5 0

3 years ago