Answer:
1/2 wWBb , White wool and brown eyes.
1/2 wWbb , White wool and blue eyes.
Explanation:
White wool (W) is dominant over black wool (w).
Brown eyes (B) is dominant over blue eyes (b).
A sheep with black wool (ww) and brown eyes (Bb) is crossed with a sheep with white wool (WW) and blue eyes (bb).
<h3>wwBb x WWbb</h3>
If there is independent assortment between genes, the genotypes of the first parent's gametes will be wB and wb. The gametes of the second parent can only be Wb.
<u>The resulting offspring will be:</u>
- 1/2 wWBb , White wool and brown eyes.
- 1/2 wWbb , White wool and blue eyes.
Answer:
The correct answer is - 2 genes.
Explanation:
The number of genes involved in the coloration of the strain of cereal grain, could be either dark tan, medium-dark tan, medium tan, light tan, or cream-colored if all F1 are medium tan when crossed a dark tan crossed with cream-colored, can be calculated as follow:
suppose there are only two gene - TT dominant over tt and CC dominant over cc
then the cross would be - RRCC - rrcc
gametes - RC and rc
Cross F1: RrCc
Self cross in F2:
offspring by Punnet cross are:
RRCC -->1/16
RRCc, RrCC .---> 4/16
RrCc, RRcc, rrCC--->6/16
rrCc, Rrcc--->4/16
rrcc ----> 1/16
thus, the correct answer is 2 genes
C.<span>trees going dormant in winter to survive unfavorable conditions</span>
