Answer:
The quantity of water drain after x min is 50
Step-by-step explanation:
Given as :
Total capacity of rain barrel = 50 gallon
The rate of drain = 10 gallon per minutes
Let The quantity of water drain after x min = y
Now, according to question
The quantity of water drain after x min = Initial quantity of water × ![(1-\dfrac{\textrm rate}{100})^{\textrm time}](https://tex.z-dn.net/?f=%281-%5Cdfrac%7B%5Ctextrm%20rate%7D%7B100%7D%29%5E%7B%5Ctextrm%20time%7D)
I.e The quantity of water drain after x min = 50 gallon × ![(1-\dfrac{\textrm 10}{100})^{\textrm x}](https://tex.z-dn.net/?f=%281-%5Cdfrac%7B%5Ctextrm%2010%7D%7B100%7D%29%5E%7B%5Ctextrm%20x%7D)
or, The quantity of water drain after x min = 50 gallon × ![(0.9)^{x}](https://tex.z-dn.net/?f=%280.9%29%5E%7Bx%7D)
Hence the quantity of water drain after x min is 50
Answer
Answer: Her total savings are equal to $11,000.
Step-by-step explanation:
Hi, to answer this question we have to write an equation.
The total savings (x) multiplied by the percentage in bonds (in decimal form) must be equal to $2,200.
Mathematically speaking:
x (20/100) = 2,200
Solving for x:
x = 2,200/ 0.2
x = $11,000
Her total savings are equal to $11,000.
Feel free to ask for more if needed or if you did not understand something.
La formula para sacar la pendiente:
Y2-Y1/X2-X1
Respuesta:
Y2-Y1/X2-X1= -2-(-10)/-1-(-1)
= -2+10/ -1+1= 8
R=8
Espero que te sirva
Y=5x+11 using the point-slope formula and simplifying