The plane that is highlighted inside the given cuboid is called a Rectangle.
<h3>What is the Plane in the given solid?</h3>
A cross-section is the intersection of a solid and a plane. Plane Figures and defined as solid shapes.
In geometry, shapes are the forms of objects which have boundary lines, angles and surfaces. These figures demonstrate the shape of objects we see in our everyday lives. There are different types of 2D shapes and 3D shapes. The plane shapes are two-dimensional closed shapes with no thickness and are known as 2D shapes.
Solid shapes are nothing but solids with three dimensions: length, breadth, and height. Solid shapes are also known as 3D shapes.
Now, looking at the given figure we see that it is a cuboid and we see that the 2 dimensional plane cut through it is clearly a rectangle.
Thus, we can conclude that the plane that is highlighted inside the given cuboid is called a Rectangle.
Read more about Plane in Solid at; brainly.com/question/1609720
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A linear equation cannot be used.
because 60/1 isn't equal to 70/5 and isn't equal to 80/20 and so on.
1/2 x > 0.4x
where Robert's spending is greater than Rosa's spending.
Allowance of Rosa = Allowance of Robert
let x = allowance
Rosa : video games = 0.4(x) ; pizza = 2/5 (x)
Robert : video games = 1/2 (x) ; pizza = 0.25 (x)
let us assume that their allowance is 100 each week. so, x = 100
Rosa : video games = 0.40(100) = 40
pizza 2/5 (100) = 200/5 = 40
total spending: 40 + 40 = 80
Robert : video games = 1/2 (100) = 50
pizza 0.25 (100) = 25
total spending: 50 + 25 = 75
Spending on video games
Rosa = 40
Robert = 50
Robert spent more of his allowance on video games than Rosa.
1/2 x > 0.4x
Answer:
Step-by-step explanation:
Solving for the variable 
, given that :
We can first start start by subtracting 
from both sides of the equation:
Now, we can divide both sides of the equation by the coefficient of , which would be 
:
Applying the fraction rule 
:
Then, apply the fraction rule 
Answer:
D) 0 = 2(x + 5)(x + 3)
Step-by-step explanation:
Which of the following quadratic equations has no solution?
We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.
A) 0 = −2(x − 5)2 + 3
0 = -2(x - 5) × 5
0 = (-2x + 10) × 5
0 = -10x + 50
10x = 50
x = 50/10
x = 5
Option A has a solution of 5
B) 0 = −2(x − 5)(x + 3)
Take each of the factors and equate them to zero
-2 = 0
= 0
x - 5 = 0
x = 5
x + 3 = 0
x = -3
Option B has a solution by one of its factors as a positive value of 5
C) 0 = 2(x − 5)2 + 3
0 = 2(x - 5) × 5
0 = (2x -10) × 5
0 = 10x -50
-10x = -50
x = -50/-10
x = 5
Option C has a solution of 5
D) 0 = 2(x + 5)(x + 3)
Take each of the factors and equate to zero
0 = 2
= 0
x + 5 = 0
x = -5
x + 3 = 0
x = -3
For option D, all the values of x are 0, or negative values of -5 and -3.
Therefore the Quadratic Equation for option D has no solution.
