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skelet666 [1.2K]
2 years ago
15

Help me for brainlist

Mathematics
1 answer:
igor_vitrenko [27]2 years ago
5 0

Answer:

1. g. $0.10 per square inch

2. c. $0.08 per square inch

3. f. $10

4. m. $8

5. h. 79 in²

6. j. 113 in²

Step-by-step explanation:

1. A = πr²

   r = diameter ÷ 2 = 10 ÷ 2 = 5

   A = π(5)² = 25π in² ≈ 78.53981

   $8.00/25π = $0.10 per square inch

2. A = πr²

   r = diameter ÷ 2 = 12 ÷ 2 = 6

   A = π(6)² = 36π in² ≈ 113.0973355

   $10.00/36π = 0.088419 = $0.08 per square inch

3. information/answer was provided

4. information/answer was provided

5. A = πr²

   r = diameter ÷ 2 = 10 ÷ 2 = 5

   A = π(5)² = 25π in² ≈ 79 in²

6. A = πr²

   r = diameter ÷ 2 = 12 ÷ 2 = 6

   A = π(6)² = 36π in² ≈ 113 in²

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35 POINTS AVAILABLE
aliina [53]

Answer:

Part 1) The length of each side of square AQUA is 3.54\ cm

Part 2) The area of the shaded region is (486\pi-648)\ units^{2}

Step-by-step explanation:

Part 1)

<em>step 1</em>

Find the radius of the circle S

The area of the circle is equal to

A=\pi r^{2}

we have

A=25\pi\ cm^{2}

substitute in the formula and solve for r

25\pi=\pi r^{2}

simplify

25=r^{2}

r=5\ cm

<em>step 2</em>

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

SU=r=5\ cm

Let

x------> the length side of the square

Applying the Pythagoras Theorem

5^{2}=x^{2} +x^{2}

5^{2}=2x^{2}

x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

<em>Find the area of the larger circle</em>

The area of the circle is equal to

A=\pi r^{2}    

we have

r=AB=18\ units

substitute in the formula

A=\pi (18)^{2}=324\pi\ units^{2}

step 2

Find the length of each side of square BCDE

we have that

AB=18\ units

The diagonal DB is equal to

DB=(2)18=36\ units

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

36^{2}=x^{2} +x^{2}

1,296=2x^{2}

648=x^{2}

x=\sqrt{648}\ units

step 3

Find the area of the square BCDE

The area of the square is

A=(\sqrt{648})^{2}=648\ units^{2}

step 4

Find the area of the smaller circle

The area of the circle is equal to

A=\pi r^{2}    

we have

r=(\sqrt{648})/2\ units

substitute in the formula

A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}  

step 5

Find the area of the shaded region

324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}

7 0
3 years ago
The endpoints of are A(2, 2) and B(3, 8). is dilated by a scale factor of 3.5 with the origin as the center of dilation to give
goldfiish [28.3K]

Answer:

The given line segment whose end points are A(2,2) and B(3,8).

Distance AB is given by distance formula , which is

if we have to find distance between two points (a,b) and (p,q) is

=  \sqrt{(p-a)^2+(q-b)^2}

AB= \sqrt{(3-2)^2+(8-2)^2}=\sqrt{1+36}=\sqrt{37} = 6.08 (approx)

Line segment AB is dilated by a factor of 3.5 to get New line segment CD.

Coordinate of C = (3.5 ×2, 3.5×2)= (7,7)

Coordinate of D = (3.5×3, 3.5×8)=(10.5,28)

CD = AB × 3.5

CD = √37× 3.5

     = 6.08 × 3.5

= 21.28 unit(approx)

2. Slope of line joining two points (p,q) and (a,b) is given by

m=\frac{q-b}{p-a}

m= \frac{8-2}{3-2}=6

As the two lines are coincident , so their slopes are equal.

Slope of line AB=Slope of line CD = 6




6 0
3 years ago
Read 2 more answers
Is the following shape a square? How do you know?
Troyanec [42]

Answer:

B

Step-by-step explanation:

it is a rectangle. each opposite sides ARE parallel but not every side is equal like a square so B

8 0
3 years ago
Choose the table that represents g(x) = −2⋅f(x) when f(x) = x + 4
fomenos

Answer:

  x g(x)

  1 −10

  2 −12

  3 −14

Step-by-step explanation:

Substitute the values and do the arithmetic.

Table values for x are 1, 2, 3. We only need to find g(1) to determine which table is the correct choice.

  f(1) = 1 +4 = 5 . . . . . . . . . put 1 where x is and do the arithmetic

 g(1) = -2·f(1) = -2·5 = -10 . . . . . matches the 3rd choice

6 0
3 years ago
Find all the real zeros of <br><br> f(x)=3x^3-9x^2+3x-9 <br><br><br> Can someone help me please
vaieri [72.5K]

Answer:

x=0,3

Step-by-step explanation:

start by dividing every term by 3

x^3-3x^2+x-3

group into 2 terms

(x^3-3x^2)+(x-3)

simplify as much as you can

x^2(x-3)+(x-3)

combine terms

(x^2)(x-3)

x=3, 0

4 0
3 years ago
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