Missing in your question the K constant value =2.99X10^-7
The reaction equation:
SOCl2 ⇄ SO2 +Cl2
initial 0.195 0 0
-X +X +X
final (0.195-X) X X
K= [SO2][Cl2]/SOCl2
by substitution
2.99X10^-7 = (X)(X)/(0.195-X)
2.99X10^-7 = X^2 / (0.195-X) by solving this equation
∴X = 0.00024 = 2.4 X10^-4
∴[Cl2] = 2.4X10^-4 m
0.499 mol
Explanation: M(CaC2) = 64.1 g/mol, n= m/M = 32.0 g/ 64.1 g/ mol= 0.499 mol
Amount of Calcium hydroxide Is same
Answer:
Approximately 
.
Explanation:
Convert both volumes to standard units (that is: liters.)
.
.
Number of moles of 
initially present (in the 
solution at 
.)
.
Number of moles of 
from the titration:
.
neutralizes at a 
ratio:
.
Hence, 
.
.
The correct answer to this question is "5." the oxidation number of cl in ClO3 will be a positive 5 because oxygen is naturally a -2 charge. times that by three and then account for the negative charge of the CLO3- ion.
