Answer:
The concentration of reactants have no effect on the rate of reaction.
Explanation:
The strength of the nucleophile doesn't affect the reaction rate of an SN1 since the nuleophile is not involved in the rate determining step. Increasing the concentration of the substrate (which is a reactant) increases the rate of reaction even though increasing the concentration of the nucleopohile has no effect on the rate of reaction. The use of polar protic solvents assist an SN1 reaction hence the solvent used can affect the rate of reaction. However, temperature affects an SN1 reaction. Increasing the temperature will increase the rate of E1 elimination reaction rather than the SN1 reaction since the both are competing reactions. Lowering the temperature favours SN1 reaction. Hence the answer.
Answer:
NaCl will only conduct electricity in solutions
Explanation:
For electrical conduction, free mobile electrons as seen in most metals must be present or ions which are charged particles must be available for solutions and molten substances.
- Sodium chloride is an ionic compound without free mobile electrons or ions despite being ionic.
- It will maintain a subtle and unique charge stability when in solid form.
- In solid, the ions are not free to move and remain locked up in the solid mass.
- When introduced into a solution, the ions becomes free to move and this will aid electrical conduction.
Answer:
4.8 mol
Step-by-step explanation:
The <em>balanced equation</em> is
Fe₂O₃ + Ca₃(PO₄)₂ ⟶2FePO₄ + 3CaO
You want to convert moles of Fe₂O₃ to moles of CaO.
The molar ratio is 3 mol CaO:1 mol Fe₂O₃.
Moles of CaO = 1.6 mol Fe₂O₃ × (3 mol CaO/1 mol Fe₂O₃)
Moles of CaO = 4.8 mol CaO
The reaction will produce 4.8 mol of CaO.
Answer:
Age of rock = 6.12 × 10³ years
Note: The question is incomplete.A similar but complete question is given below.
The half-life for the radioactive decay of carbon-14 to nitrogen-14 is 5.73 x 10^3 years. Suppose nuclear chemical analysis shows that there is 0.523mmol of nitrogen-14 for every 1.000 mmol of carbon-14 in a certain sample of rock.
Calculate the age of the rock. Round your answer to 2 significant digits.
Explanation:
The half-life of a radioactive material is the time taken for half the atoms in the atomic nucleus of a material to disintegrate.
The half-life for the radioactive decay of carbon-14 to nitrogen-14 is given as 5.73 x 10³ years. This means that given 1 mole of carbon-14 is present initially, after one half-life, 0.5 moles of carbon-14 would remain.
Number of millimoles of carbon-14 remaining = 1 - 0.523 = 0.477 mmol
Number of half-lives that the carbon-14 has undergone is determined as follows:
Amount remaining = (1/2)ⁿ
where nnis number of half-lives
0.5 mmol = one half-life
0.5 = (1/2)¹
O.477 = (1/2)ⁿ = (0.5)ⁿ
㏒₀.₅(0.477) = n
n = ㏒(0.477)/㏒(0.5)
n = 1.067938829
Age of the rock = number of half-lives × half-life
Age of rock = 1.067938829 × 5.73 × 10³ years
Age of rock = 6.12 × 10³ years