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miv72 [106K]
4 years ago
9

What mass of oxygen forms from 71.89 g CO2? Use the periodic table to find molar masses. 71.89 g CO2 =  ------ g O2

Chemistry
1 answer:
andre [41]4 years ago
7 0
We use the ratio of the atoms C and O from the chemical formula. We calculate as follows:

71.89 g CO2 ( 1 mol CO2 / 44.01 g CO2 ) (1 mol O2 / 1 mol CO2) (32 g O2 / 1 mol ) = 52.27 g O2

Therefore, 

71.89 g CO2 =  52.27 <span>g O<span>2</span></span>
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If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?
ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}  where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation:  T_C+273=T_K

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, T_1 = 273[K], and T_2 = (49.4+273)[K]=322.4[K].

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}

\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})

1810.04571428[mL]=V_2

Adjusting for significant figures, this gives V_2=1810[mL]

4 0
2 years ago
PLZ HELP ME
mariarad [96]

The balanced reaction is 3 Ca ( s ) + N 2 ( g )  →  Ca 3 N 2 ( s ).

<u>Explanation</u>:

A chemical equation is said to be balanced when the total number of atoms present on the reactants side is equal to the total number of atoms present on the product side.

The unbalanced chemical equation is as follows,

                             Ca ( s ) + N 2 ( g )  →  Ca 3 N 2 ( s )

To balance this equation, you need to look at how many atoms of each element are present on each side of the chemical equation.

 Calcium has  1  atom on the reactant and  3  on the products side. To balance the reaction we need to multiply the calcium atom by  3  on the reactants side.

                            3 Ca ( s ) + N 2 ( g )  →  Ca 3 N 2 ( s )    

Now  Nitrogen has a coefficient of  2  on both sides of the reaction. Hence the balanced chemical equation will thus be

                              3 Ca ( s ) + N 2 ( g )  →  Ca 3 N 2 ( s )

3 0
3 years ago
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