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olya-2409 [2.1K]
3 years ago
9

Two customers went to a restaurant to buy drinks

Mathematics
1 answer:
aev [14]3 years ago
7 0

Answer:

the cost for each drink = $2.54

Step-by-step explanation:

The statement formed a simultaneous equation :

3x + 6y = $21.12

4x + 9y = $30.41

solving simultaneously,you have that ; x = 2.54, y = 2.25

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Sally's average grade in math is a 76 ,but this is not her final grade. Sally takes her Math exam she got a 61 % and the final i
Aloiza [94]
Use the equation:

76 * .8 + 61 * .2 = Final Grade
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3 years ago
By definition pH = - log H+], where H*] is the hydrogen concentration in $ ltext(moles per liter]$. If the pH
Ivanshal [37]

A ........................ig

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pedro open his account with $710 and withdraw $35 per week. maria opened her account with $570 and withdrew $25 weekly .In how m
user100 [1]
In 14 weeks, if you turn both of those into equations you'll get

y =  - 35x + 710
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6 0
4 years ago
PLEASE PLEASE HELP!! Sketch a triangle and label correctly. Work must be shown for this problem. Round answers to the nearest hu
torisob [31]

Answer:

Please see attached image for the sketch with the labels.

Length "x" of the ramp = 11.70 ft

Step-by-step explanation:

Notice that the geometry to represent the ramp is a right angle triangle, for which we know one of its acute angles (20^o), and the size of the side opposite to it (4 ft). Our unknown is the hypotenuse "x" of this right angle triangle, which is the actual ramp length we need to find.

For this, we use the the "sin" function of an angle in the triangle, which is defined as the quotient between the side opposite to the angle, divided by the hypotenuse, and then solve for the unknown "x" in the equation:

sin(20^o)=\frac{opposite}{hypotenuse}\\ sin(20^o)=\frac{4}{x} \\x=\frac{4}{sin(20^o)} \\x=11.695\,\,ft

Therefore the length of the ramp rounded to the nearest hundredth as requested is: 11.70 ft

5 0
3 years ago
Let Y1 and Y2 have the joint probability density function given by:
Ann [662]

Answer:

a) k=6

b) P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

Step-by-step explanation:

a) if

f (y1, y2) = k(1 − y2), 0 ≤ y1 ≤ y2 ≤ 1,  0, elsewhere

for f to be a probability density function , has to comply with the requirement that the sum of the probability of all the posible states is 1 , then

P(all possible values) = ∫∫f (y1, y2) dy1*dy2 = 1

then integrated between

y1 ≤ y2 ≤ 1 and 0 ≤ y1 ≤ 1

∫∫f (y1, y2) dy1*dy2 =  ∫∫k(1 − y2) dy1*dy2 = k  ∫ [(1-1²/2)- (y1-y1²/2)] dy1 = k  ∫ (1/2-y1+y1²/2) dy1) = k[ (1/2* 1 - 1²/2 +1/2*1³/3)-  (1/2* 0 - 0²/2 +1/2*0³/3)] = k*(1/6)

then

k/6 = 1 → k=6

b)

P(Y1 ≤ 3/4, Y2 ≥ 1/2) = P (0 ≤Y1 ≤ 3/4, 1/2 ≤Y2 ≤ 1) = p

then

p = ∫∫f (y1, y2) dy1*dy2 = 6*∫∫(1 − y2) dy1*dy2 = 6*∫(1 − y2) *dy2 ∫dy1 =

6*[(1-1²/2)-((1/2) - (1/2)²/2)]*[3/4-0] = 6*(1/8)*(3/4)=  9/16

therefore

P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

8 0
3 years ago
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