Answer:
84 is what you get when you add them
14 is what you get when you factor their GCF then add
hope this helps plz mark brainliest
Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
This statment only works for linear systems because in non-linear systems it is okay to have more than one soultion
but if the system is linear than you can define it by it two soultions or in other words it takes two points to form a line and if two lines pass through the same points then you can define them by those point and they are the same line
Answer: $25
Step-by-step explanation:
t = t-shirts
3t + 15 = 90
3t = 75
t = 25
There are no real solutions
