How to find components of a vector given magnitude and angle?
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Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side. The height of the tringle is 24 units. Hence option 2 is the correct option.
<h3>Given information-</h3>The triangle for the given problem is shown in the image below.
Form the figure the length of the each side is units.
As all the sides are equal thus the is a equilateral triangle in which the height of the divides the triangle into two equal part of the length
at point <em>R.</em>
Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side.
Now in the , the length of the hypotenuse is
units and the length of the base is
units. Let <em>h </em>is the height of the triangle thus by the Pythagoras theorem,
Solve for <em>h,</em>
<em />
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Thus the height of the tringle is 24 units. Hence option 2 is the correct option.
Learn more about the equilateral triangle here;
Q(p) = k/p^3 . . . . . . . . we want to find k
q(10) = k/10^3 = 64
k = 64,000
Revenue = q(p)*p = 64000/p^2
Cost = 150 +2q = 150 +2*64000/p^3
Profit = Revenue -Cost = 64000/p^2(1 -2/p) -150
Differentiating to find the maximum profit, we have
.. dProfit/dp = -2(64000/p^3) +6(64000/p^4) = 0
.. -1 +3/p = 0
.. p = 3
A price of $3 per unit will yield a maximum profit.
q(10) = k/10^3 = 64
k = 64,000
Revenue = q(p)*p = 64000/p^2
Cost = 150 +2q = 150 +2*64000/p^3
Profit = Revenue -Cost = 64000/p^2(1 -2/p) -150
Differentiating to find the maximum profit, we have
.. dProfit/dp = -2(64000/p^3) +6(64000/p^4) = 0
.. -1 +3/p = 0
.. p = 3
A price of $3 per unit will yield a maximum profit.
First get all the terms on the same side:
Now solve using the quadratic formula which is:
Plug in the values:
So the answer is:
Now solve using the quadratic formula which is:
Plug in the values:
So the answer is: