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Construct the 90% confidence interval for the proportion of students at the college who have completed their required English 10

igomit [66]

Answer:

The confidence interval has an lower limit of $\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}$ and an upper limit of $\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}$ , in which $\pi$ is the sample proportion and $n$ is the size of the sample.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}$

The confidence interval has an lower limit of $\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}$ and an upper limit of $\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}$ , in which $\pi$ is the sample proportion and $n$ is the size of the sample.

8 0

4 years ago

!!!!How many solutions does the equation have?

Margaret [11]

No solution bc the equations aren't equal to each other

3 0

3 years ago

Read 2 more answers

What's the sum of all numbers less than 10,000 that are divisible by 2, 3, and 5??

Akimi4 [234]

It has a factor of 2*3*5=30
what is the biggest number that is a multipule of 30

hmm
9000
9900
9990 is the biggest
30*333=9990
the summation of an arithetic sequence where first term is a1 and last is an and the number of terms is n
$s= \frac{n(a1+an)}{2}$

30 *2=60
that's 2 terms
30*3=90
30,60,90
3 terms

so 30*n means n terms
9990=30*333 means 333 terms

n=333
a1=30
an=9990
$s= \frac{333(30+9990)}{2}$
$s= \frac{333(10020)}{2}$
$s= \frac{3336660}{2}$
s=1668330

answer is 1,668,330

8 0

3 years ago

The table below shows two equations:

Kobotan [32]

Answer:

First x=-2

Second x= -11.94

Step-by-step explanation:

1 |2x-3|+5=4

2x+3+5=4

2x+8=4

2x=-4

Divide by 2 for both parties

X = -2

Number 2

215x +31-10=3

215x+21=3

215x= -18

Divide by 215 on both sides

X= - 11.94

8 0

4 years ago

20 POINTSSSS

marta [7]

Step-by-step explanation:

Commission earned

= 1/32 * Total sales

= 1/32 * $24,000

= $750.

4 0

3 years ago