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3 years ago

Please help? i’m not good with math at all- ^^ that’s embarrassing

Mathematics

1 answer:

Nata [24]3 years ago

6 0

Answer:

The answer is A. If not then I'm sorry ☹

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Write in slope intercept form, then convert to standard form Slope=1, y-intercept=-3

Viktor [21]

Slope = 1

y-intercept = -3, which can be expressed as (0,-3).

y - y_1 = m(x - x_1)

y -(-3) = 1(x - 0)

y + 3 = x

The slope-intercept form is

y = x - 3.

The standard form is Ax + By = C.

y = x - 3

3 = x - y

Done.

6 0

3 years ago

What -7 x4=36? amogus amogus amogus amogus

77julia77 [94]

Based on the given problem of -7x⁴ = 36, the solution to the equation is x = -1.5.

<h3>What is the solution to this problem?</h3>

The equation to find x is given as:

-7x⁴ = 36

Solving it gives:

-7x⁴ = 36

x⁴ = 36/-7

x⁴ = -36/7

x = ⁴√(-36/7)

x = -1.5

In conclusion, x is -1.5.

Find out more questions on solving for x at brainly.com/question/2910769

#SPJ1

3 0

1 year ago

Evaluate 3r³+5,when r=2

Elza [17]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Assessment items What is the quotient? 1 5/8 ÷(−1 3/5 )

Solnce55 [7]

We need convert the mixed numbers to improper fractions.

$1\dfrac{5}{8}=\dfrac{1\cdot8+5}{8}=\dfrac{8+5}{8}=\dfrac{13}{8}\\\\1\dfrac{3}{5}=\dfrac{1\cdot5+3}{5}=\dfrac{5+3}{5}=\dfrac{8}{5}$

Divide the number by a fraction, this is the same as multiply this number by the reciprocal of the fraction:

$1\dfrac{5}{8}\div\left(-1\dfrac{3}{5}\right)=-\dfrac{13}{8}\div\dfrac{8}{5}=-\dfrac{13}{8}\cdot\dfrac{5}{8}=-\dfrac{(13)(5)}{(8)(8)}=-\dfrac{65}{64}\\\\\boxed{1\dfrac{5}{8}\div\left(-1\dfrac{3}{5}\right)=-1\dfrac{1}{64}}$

4 0

3 years ago

Felicia wants to build a kite with the shape shown. If AC is 60 cm, how many centimeters are in the length of BD?

Kay [80]

Answer:

Step-by-step explanation:

By applying tangent rule in the given right triangle AOB,

tan(30°) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

$\frac{1}{\sqrt{3}}=\frac{BO}{OA}$

$OA=BO(\sqrt{3})$

By applying tangent rule in the given right triangle BOC,

tan(60°) = $\frac{OC}{BO}$

OC = BO(√3)

OA + OC = AC

$BO(\sqrt{3})+BO(\sqrt{3}) =60$

2√3(BO) = 60

BO = 10√3

OC = BO(√3)

OC = (10√3)(√3)

OC = 30

By applying tangent rule in right triangle DOC,

tan(60°) = $\frac{OD}{OC}$

OD = OC(√3)

OD = 30√3

Since, BD = BO + OD

BD = 10√3 + 30√3

BD = 40√3

≈ 69.3

6 0

3 years ago