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mamaluj [8]
2 years ago
15

HELP NO LINKS Jesse wants to start driving himself to and from school each day his parents want to know how much driving time wo

uld be involved so Jesse surveyed for neighbors who live on his block and drive to school data he collected is displayed in the table below

Mathematics
1 answer:
DIA [1.3K]2 years ago
4 0
The answer is B. have a good thanksgiving
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Can someone solve this?
aleksley [76]

Answer:

Considering the Law of Cosines:

c^2=a^2+b^2-2ab*cosC

a=14mi; b=24mi; c=CA; C=91degrees

\cos \left(91^{\circ \:}\right)=-0.01745\dots

c^2=14^2+24^2-2(14)(24)*\cos \left(91^{\circ \:}\right)\\c^2=196+576-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*(-0.01745)\\c^2=772+11.7264\\c=\sqrt{772+11.7264} \\c=\sqrt{783.7264}\\c=27.99mi

4 0
3 years ago
5
Snowcat [4.5K]
F(1) = 2
f(2) = 3f(1) = 3(2) = 6
f(3) = 3f(2) = 3(6) = 18 (A)
5 0
2 years ago
Read 2 more answers
The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct
lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

y=\dfrac{x}{1+x}

Point P\left(1,\dfrac{1}{2}\right) lies on the curve.

Point Q\left(x,\dfrac{x}{1+x}\right) is an arbitrary point on the curve.

The slope of the secant line PQ is

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]

1. If x=0.5, then the slope is

\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333

2. If x=0.9, then the slope is

\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632

3. If x=0.99, then the slope is

\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513

4. If x=0.999, then the slope is

\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501

5. If x=1.5, then the slope is

\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2

6. If x=1.1, then the slope is

\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381

7. If x=1.01, then the slope is

\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488

8. If x=1.001, then the slope is

\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499

7 0
3 years ago
A business could not collect $5,000 that it was owed. The total owed to the business was $100,000. What fraction of the total wa
son4ous [18]

Total owed to the business = $100,000

amount that could not be collected = $5000

Fraction of total not collected

\text{fraction not collected=}\frac{5000}{100000}=\frac{5}{100}=\frac{1}{20}

3 0
1 year ago
What is the least common denominator used to add the fractions 1/18 and 5/12
Ne4ueva [31]

Answer:

6

Step-by-step explanation:

Im right

7 0
3 years ago
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