Using the z-distribution, a sample size of 180 is needed for the estimate.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:
The margin of error is given by:
In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 98% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 2.327.
The population standard deviation is of 
, and to find the sample size, we have to solve for n when M = 4.
Hence:
n = 179.03.
Rounding up, as a sample size of 179 would result in an error slightly above 4, a sample of 180 is needed.
More can be learned about the z-distribution at brainly.com/question/25890103
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Since this is a compound interest, we will use this formula: A = P(1+r/n)^n*t
P = $1000 --> the amount that we start with
r = 8% --> this is the rate
n = 4 --> This is because it is compounded quarterly.
t = 5 --> the amount of years
A = 1,000.00(1 + 0.02)^(20)
So our final value after inserting those numbers in the equation is: $1,485.95.
3.75, to do this do 15*.25
Answer:
the possible amounts that he will spend is $29-$15=$14
First, to make the equation easier to read, you want to add the x’s together. you should then get 2.6x-3.8=-9. then, you want to add the 3.8 to both sides, to make the x stand alone. you should end up with 2.6x=-5.2. to find x, you then want to divide both sides by 2.6. your final answer after dividing should be x=-2
