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3 years ago

A3/8

Mathematics

1 answer:

mart [117]3 years ago

5 0

Answer:

A.)130 80

Step-by-step explanation:

1y/3x

-8x/1xy

answer:130 80

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What is the area of the triangle? 6 18 units

sweet [91]

Answer:

54 units

Step-by-step explanation:

multiply 6 x 18 = 108 and divide by 2 to get 54. The equation for the area of a triangle is base x height divided by 2.

4 0

3 years ago

Read 2 more answers

Write an equation in slope-intercept form for the following line: (-14.1) and (13,-2)

vesna_86 [32]

Answer:

$y=-\frac{1}{9}x-\frac{5}{9}$

Step-by-step explanation:

$(-14,1)(13,-2)$

Use the slope-intercept formula:

$y=mx+b$

m is the slope and b is the y-intercept. Use the slope formula first:

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =\frac{rise}{run}$

Rise over run is the change in the y-axis over the change in the x-axis. Plug in the coordinates:

$(-14(x_{1}),1(y_{1}))\\(13(x_{2}),-2(y_{2}))$

$\frac{-2-1}{13-(-14)}$

Simplify parentheses (two negatives makes a positive):

$\frac{-2-1}{13+14}$

Simplify:

$\frac{-3}{27} =-\frac{3}{27}=-\frac{1}{9}$

The slope is $-\frac{1}{9}$ . Insert into the equation:

$y=-\frac{1}{9}x +b$

Now, to find the y-intercept, take one of the points and substitute for the x and y values of the equation:

$(13,-2)\\-2=-\frac{1}{9} (13)+b$

Solve for b, the y-intercept. Simplify parentheses:

$-\frac{1}{9}*\frac{13}{1}=-\frac{13}{9}$

$-2=-\frac{13}{9} +b$

Add $-\frac{13}{9}$ to both sides:

$-2+\frac{13}{9}=-\frac{13}{9} +\frac{13}{9} +b\\\\-2+\frac{13}{9} =b$

Simplify:

$-\frac{2}{1} +\frac{13}{9}\\\\-\frac{18}{9}+\frac{13}{9}\\ \\b=-\frac{5}{9}$

The y-intercept is $-\frac{5}{9}$ . Insert this into the equation:

$y=-\frac{1}{9} x-\frac{5}{9}$

Finito.

8 0

3 years ago

at a point P on the parabola x^2=4ay a normal PK is drawn. From vertex O, a perpendicular OM is drawn to meet the normal at M. S

saveliy_v [14]

Answer: Its too long to write here, so I will just state what I did. I let P=(2ap,ap^2) and Q=(2aq,aq^2) But x-coordinates of P and Q differ by (2a) So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2) So Q=(2a(p-1), aq^2) which means, 2aq = 2a(p-1) therefore, q=p-1 then I subbed that value of q in aq^2 so Q=(2a(p-1), a(p-1)^2) and P=(2ap,ap^2) Using these two values, I found the midpoint which was: M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 ) then x = a(2p-1) rearranging to make p the subject p= (x+a)/2a

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3 years ago

The number of species of coastal dune plants in australia decreases as the latitude, in °s, increases. There are 34 species at 1

Bas_tet [7]

We have been given that the number of species of coastal dune plants in Australia decreases as the latitude, in °s, increases.

Further we know that there are 34 species at 11°s and 26 species at 44°s.

We can express the given information at two ordered pairs as shown below:

$(n,l)=(11,34)\text{ and }(n,l)=(44,26)$