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Blababa [14]
3 years ago
10

Convert the following repeating decimal to a fraction in simplest form .53

Mathematics
1 answer:
galben [10]3 years ago
5 0

9514 1404 393

Answer:

  53/99

Step-by-step explanation:

When an n-digit repeat begins at the decimal point, the repeating digits can be placed over an equal number of 9s to make a fraction. Sometimes, that fraction can be reduced to lower terms.

  0.\overline{53}=\boxed{\dfrac{53}{99}}

__

If the repeat does not start at the decimal point, the conversion can be done as follows.

For a number x with a decimal fraction that has n digits repeating, multiply by 10^n, subtract x and then divide by (10^n -1).

The fraction will be ...

  (x·10^n -x)/(10^n -1) . . . where x has n repeating digits in the decimal fraction

Here, that looks like ...

  x=0.\overline{53}\\100x=53.\overline{53}\\100x-x=53.\overline{53}-0.\overline{53}=53\\99x=53\\x=\dfrac{53}{99}

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For the function, f(x)=(9x+7)/(2x+4)
AVprozaik [17]
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C. f(x)=\frac{9x+7}{2x+4}\\f(0)=\frac{9(0)+7}{2(0)+4}\\f(0)=\frac{7}{4}\\f(0)=1.75\\f(5)=\frac{9(5)+7}{2(5)+4}\\f(5)=\frac{45+7}{10+4}\\f(5)=\frac{52}{14}\\f(5)=\frac{26}{7}\\f(5)=3.714 - The absolute maximum is f(5) = 26/7 or 3.714. The absolute mimimum is f(0) = 1.75. This applies to the interval [0, 5]. Proof: graph f(x) at [0, 5] on a graph or graphing calculator.
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3 years ago
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